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My name is Ann [436]
3 years ago
10

For questions 1 and 2, simplify the expression. Then, identify the terms, constants, and coefficients of the simplified expressi

on.
1. 8x2 - 3x + 6x2 + 5x - 9



2. 5(2x + 4) + 3x



For question 3, translate the verbal expression to an algebraic expression. Then, identify the terms, constants, and coefficients.

3. The product of three and x, added to 4



4. Explain what the expression 7(3x) does not equal 21x, but (5*2)x does equal 10x.



5. A bank account balance for an account with an initial deposit of P dollars eans interest at an annual rate of r. The amount of money in the account after n years is described using the following expression: P(1+r)n. What effect does increasing the value of r have on the amount of money after n years?



6. A cell phone company bills on a monthly basis. Each bill includes a $19.95 service fee (which includes 500 minutes), a $3.95 tax, and a $0.15 per minute fee for each minute over the first 500 minutes. Write an expression that describes the cost of a month's bill. Then, tell how the expression would change if the service fee were reduced.
Mathematics
1 answer:
natta225 [31]3 years ago
5 0

Answer:

are the first 2 power of two like ur question is confusing

Step-by-step explanation:

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A chain of retail computer stores opened 2 stores in its first year of operation. After 8 years of operation, the chain consiste
Helen [10]

Answer:

0.66

Step-by-step explanation:

The exponential growth equation is expressed as;

S(t) = S0e^kt

S(t) is the number of stores after t years

S0 is the initial number of stores

If a chain of retail computer stores opened 2 stores in its first year of operation then at t = 1, S(t) = 2. Substitute into the equation;

2 = S0e^k(1)

2 = S0e^k .... 1

Also if after 8 years of operation, the chain consisted of 206 stores, this means at t = 8, S(t) = 206. Substitute into the equation;

206 = S0e^k(1)

206 = S0e^8k .... 2

Next is to calculate the value of k

Divide equation 2 by 1;

\frac{206}{2} = \frac{S0e^{8k} }{S0e^k }\\103 =   e^{7k}\\apply \ ln \ to \ both \ sides\\ln103 = lne^{7k}\\ln103 = 7k\\k = \frac{ln103}{7}\\k = \frac{4.6347}{7} \\k =  0.6621

Hence the value of k to the nearest hundredth is 0.66

4 0
3 years ago
Heeeeelp Find the distance of AB if A (2, 6) and B (-5, 2).
evablogger [386]

Answer:

let A (2, 6) be (x1, y1)

B (-5, 2)  be (x2, y2)

distance AB =√[(x2 - x1)² + (y2 - y1)²]

                    √[(-7)²+ (-4)²]

                   √65

                   

7 0
4 years ago
A bicyclist rides the same number of miles every minute. The ratio table below shows the number of miles she rides during certai
nika2105 [10]

Answer:

B) Find the ratio of minutes to miles, 4:1. Multiply 7.5 by 4

Step-by-step explanation:

A bicyclist rides the same number of miles every minute. The ratio table below shows the number of miles she rides during certain amounts of time.

Biking Times and Distances        

Number of Minutes         Number of Miles

10                                             2.5

16                                              4

?                                              7.5

48                                              12

Which statement explains how to find the number of minutes it takes to bike 7.5 miles?

B) Find the ratio of minutes to miles, 4:1. Multiply 7.5 by 4....

5 0
3 years ago
Read 2 more answers
A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 46.046.0 and
Gala2k [10]

Answer:

The probability of selecting a class that runs between 50.2550.25 and 51.2551.25 minutes is 0.10

Step-by-step explanation:

The Uniform Distribution, also known as Rectangular Distribution, is a type of Continuous Probability Distribution. It has a continuous random variable restricted to a finite interval and its probability function has a constant density during this interval.

The formula of probability if given by:

f(x)=

\left \{ {{\frac{1}{b-a}; \ a \leq x \leq b  } \atop {0}; \ x \ otherwise } \right.

In this exercise a= 46.0 and b= 56.0

The probability of selecting a class that runs between 50.2550.25 and 51.2551.25 minutes is:

\int\limits^{51.25}_{50.25} {\frac{1}{56-46} } \, dx = \int\limits^{51.25}_{50.25} {\frac{1}{10} } \, dx = \frac{1}{10} \times (51.25 - 50.25)=\frac{1}{10}=0.1

7 0
3 years ago
You have $16 and a coupon for a $5 discount at a local
Brrunno [24]
8 bags of chips total
7 0
3 years ago
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