Answer:
Answer:
164.32 earth year
Step-by-step explanation:
distance of Neptune, Rn = 4.5 x 10^9 km
distance of earth, Re = 1.5 x 10^8 km
time period of earth, Te = 1 year
let the time period of Neptune is Tn.
According to the Kepler's third law
T² ∝ R³
![\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}](https://tex.z-dn.net/?f=%5Cleft%20%28%20%5Cfrac%7BT_%7Bn%7D%7D%7BT_%7Be%7D%7D%20%5Cright%20%29%5E%7B2%7D%3D%5Cleft%20%28%20%5Cfrac%7BR_%7Bn%7D%7D%7BR_%7Be%7D%7D%20%5Cright%20%29%5E%7B3%7D)
![\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}](https://tex.z-dn.net/?f=%5Cleft%20%28%20%5Cfrac%7BT_%7Bn%7D%7D%7B1%7D%20%5Cright%20%29%5E%7B2%7D%3D%5Cleft%20%28%20%5Cfrac%7B4.5%5Ctimes10%5E%7B9%7D%7D%7D%7B1.5%5Ctimes10%5E%7B8%7D%7D%7D%20%5Cright%20%29%5E%7B3%7D)
Tn = 164.32 earth years
Thus, the neptune year is equal to 164.32 earth year.
Step-by-step explanation: