The ratio of similar areas is the square of the ratio of the scale factor.
Circle R's sector is (5/2)² = 25/4 the area of Circle Q's sector.
well, we're assuming all along that Merina owes Bradford $2000, because in the 1st scenario, she was going to pay twice $1000.
on the 2nd scenario, she'll be paying the same $2000 but split 7 months from now and then 7 months later, same 2000 bucks, at which point Bradford applied 8.5% interest.
using those assumptions, since the wording is not quite clear, we can say that Merina is simply paying 2000 bucks plus the 8.5%
![\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{8.5\% of 2000}}{\left( \cfrac{8.5}{100} \right)2000}\implies 170 \\\\[-0.35em] ~\dotfill\\\\ \cfrac{\stackrel{principal}{2000}~~ + ~~\stackrel{interest}{170}}{2}\implies \stackrel{\textit{two equal payments of}}{1085}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Ba%5C%25%20of%20b%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20%5Cleft%28%20%5Ccfrac%7Ba%7D%7B100%7D%20%5Cright%29%5Ccdot%20b%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D~%5Chspace%7B5em%7D%5Cstackrel%7B%5Ctextit%7B8.5%5C%25%20of%202000%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B8.5%7D%7B100%7D%20%5Cright%292000%7D%5Cimplies%20170%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B%5Cstackrel%7Bprincipal%7D%7B2000%7D~~%20%2B%20~~%5Cstackrel%7Binterest%7D%7B170%7D%7D%7B2%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Btwo%20equal%20payments%20of%7D%7D%7B1085%7D)
Answer:
109.56
Step-by-step explanation:
bodmas
yeah
ahaha
Answer:
77 ft²
Step-by-step explanation:
Given that:
Surface Area of larger pyramid = 539 ft²
Scale factor of the smaller pyramid = 1/7
Tbe surface area of the smaller pyramid will be :
Scale factor * surface area
1/7 * 539ft²
= 539 ft² / 7
= 77 ft²
Answer:
- Tadeo: 12 hours
- Dylan: 2 hours
Step-by-step explanation:
We can let d represent the number of hours that Dylan volunteered. Then Tadeo volunteered for 6d hours, and their total hours were ...
d +6d = 14
7d = 14 . . . . . . collect terms
d = 2 . . . . . . . divide by the coefficient of d
6d = 6(2) = 12
Tadeo volunteered 12 hours; Dylan volunteered 2 hours.
