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Answer:
The equation of line with given slope that include given points is 3 y + x - 20 = 0
Step-by-step explanation:
According to Cora , if we know the slope and points on a line then we can write the equation of a line .
Since , The equation of line in slope-intercept form is
y = m x + c
<u>Where m is the slope of line , and if we know the points ( x , y ) which satisfy the line then constant term c can be get and the equation of line can be formed .</u>
So , From the statement said above it is clear that she is correct .
Now , Again
Given as :
Slope of a line is m = - 
That include points ( 2 , 6 )
Now from the equation of line as y = m x + c
∴ 6 = -
( 2 ) + c
Or, 6 = -
+ c
So , c = 6 +
or, c =
∴ c =
So, The equation of line can be written as
y = -
x +
Or, 3 y = - x + 20
I.e 3 y + x - 20 = 0
Hence The equation of line with given slope that include given points is 3 y + x - 20 = 0 Answer
Answer:
The equilibrium quantity is 26.4
Step-by-step explanation:
Given


Required
Determine the equilibrium quantity
First, we need to determine the equilibrium by equating Qd to Qs
i.e.

This gives:

Collect Like Terms


Solve for P


This is the equilibrium price.
Substitute 2.4 for P in any of the quantity functions to give the equilibrium quantity:



<em>Hence, the equilibrium quantity is 26.4</em>
Answer:
hello : P(A and B) = 3/20
Step-by-step explanation:
events A and B are independent:
P(A and B) = P(A)×P(B)
P(A and B) = (1/4)×(3/5)
P(A and B) =3/20
continu ....
P(B/A)= P(A and B) / P(A)