Answer:
Step-by-step explanation:
6 symbols and 4-symbol code so number of combinations wich doesn't contain the same symbol twice would be:
6•5•4•3 = 360
If code starts with a star followed by triangle that means only one posibility for first two symbols and code doesn't containing the same symbol twice means that left 4 symbols for next two.
So number of combinations of code starting with a star followed by triangle and doesn't containing the same symbol twice will be:
1•1•4•3 = 12
The probability that a randomly chosen code starts with a star followed by triangle and doesn't contain the same symbol twice:
Answer:
33
Step-by-step explanation:
For every 5 squares, two are red and three are green. So 3/5 of the squares are green.
3/5x55=33
Answer:
These triangles cannot be proved congruent
Step-by-step explanation:
The theorems for congruence are SSS SAS ASA AAS. Here, there is only one common side and one common angle marked, therefore you cannot prove congruency.
For this case we have that by definition, the line equation of the slope-intersection form is given by:
Where:
m: It's the slope
b: It is the cut-off point with the y axis
According to the statement we have:
Thus, the equation is of the form:
We substitute the given point and find "b":
Finally, the equation is of the form:
Answer:
Answer:
what the question
Step-by-step explanation:
