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andreyandreev [35.5K]
3 years ago
14

Your client’s PD is 62. The frame eyesize is 48, and the DBL is 18. When you block this lens, how much will the decentration per

lens be?
Mathematics
1 answer:
enyata [817]3 years ago
6 0

Answer:

2 mm

Step-by-step explanation:

Remember that the formula is: (DBC-PD) ÷ 2

and

DBC = DBL + frame eye size.

The correct answer is: 2 mm

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Cynthia Besch wants to buy a rug for a room that is 24 ft wide and 33 ft long. She
qaws [65]
<h3>Answer:   16 ft by 25 ft</h3>

=========================================================

Explanation:

Refer to the diagram below.

The outer dimensions 24 ft and 33 ft shrink down to 24-2x ft and 33-2x ft respectively. This subtraction of 2x is due to subtracting two copies of x per side.

The carpet has area of (24-2x)(33-2x)

Cynthia can afford to buy 400 sq ft of carpet

So we set 400 equal to that previous expression and solve for x

(24-2x)(33-2x) = 400

24(33-2x) - 2x(33-2x) = 400

792-48x - 66x + 4x^2 = 400

4x^2 - 114x + 792 = 400

4x^2 - 114x + 792-400 = 0

4x^2 - 114x + 392 = 0

From here, use the quadratic formula to isolate x.

Plug in a = 4, b = -114, c = 392

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-114)\pm\sqrt{(-114)^2-4(4)(392)}}{2(4)}\\\\x = \frac{114\pm\sqrt{6724}}{8}\\\\x = \frac{114\pm82}{8}\\\\x = \frac{114+82}{8} \ \text{ or } \ x = \frac{114-82}{8}\\\\x = \frac{196}{8} \ \text{ or } \ x = \frac{32}{8}\\\\x = 24.5 \ \text{ or } \ x = 4\\\\

The two possible solutions are x = 24.5 and x = 4

But if x = 24.5, then 24 - 2x = 24 - 2*24.5 = -25 which isn't possible. We cannot have a negative width or negative length for the carpet.

Luckily x = 4 does work since

24 - 2x = 24 - 2*4 = 16

33 - 2x = 33 - 2*4 = 25

Both results are positive.

Therefore, the carpet has dimensions of <u>16 ft by 25 ft</u>

Check: 16*25 = 400, so the answer is confirmed

5 0
1 year ago
I need help on this question hurry!!
Natasha_Volkova [10]

Answer:

(0.4,1)

Step-by-step explanation:

I hope that this is for homework and not a quiz or test.

Since we already know the value of y which is 1, we can substitute it into the equation above it.

-5x+3=1

-5x=-2

x=2/5=0.4

So in (x,y) format (0.4,1)

6 0
3 years ago
Question: is 1 &gt; 0.99999999...?<br>Prove algebraically.
Crazy boy [7]
No.  We claim that 1=0.\overline{9} and use algebra to prove the statement.

Let x=0.\overline{9}.  Multiply this by ten to get 10x=9.\overline{9}.  Subtract the initial equation to give 9x=9 and divide by 9 to see that x=1.  Substituting into the original equation gives 1=0.\overline{9}, proving the desired statement.
6 0
3 years ago
A surveyor measures the angle of elevation to a point on a mountain, that is 6 miles away, to be 15 degrees. The vertical change
cricket20 [7]
You can draw a right triangle with the informatio.

The vertical change in elevation (unknown) is the opposed leg to the angle 15°

The distance from the surveyor to the point vertically below the point on the mountain is the adjacent leg = 6 miles.

Then tan(15°) = x / 6 => x = 6tan(15) = 1.61 miles

Answer: 1.61 miles
6 0
2 years ago
Read 2 more answers
Help, i just need the answers and no need for explanations.
maria [59]

Answer:

The equation of the quadratic function shown is;

x^2+ 2x -3

Step-by-step explanation:

Here in this question, we need to know the quadratic equation whose graph was shown.

The key to answering this lies in knowing the roots of the equation.

The roots of the equation are the solution to the quadratic equation and can be seen from the graph at the point where the quadratic equation crosses the x-axis.

The graph crosses the x-axis at two points.

These are at the points x = -3 and x = 1

So what we have are;

x + 3 and x -1

Multiplying both will give us the quadratic equation we are looking for.

(x + 3)(x-1) = x(x -1) + 3(x-1)

= x^2 -x + 3x -3 = x^2 + 2x -3

3 0
3 years ago
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