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salantis [7]
3 years ago
15

Help, i just need the answers and no need for explanations.

Mathematics
1 answer:
maria [59]3 years ago
3 0

Answer:

The equation of the quadratic function shown is;

x^2+ 2x -3

Step-by-step explanation:

Here in this question, we need to know the quadratic equation whose graph was shown.

The key to answering this lies in knowing the roots of the equation.

The roots of the equation are the solution to the quadratic equation and can be seen from the graph at the point where the quadratic equation crosses the x-axis.

The graph crosses the x-axis at two points.

These are at the points x = -3 and x = 1

So what we have are;

x + 3 and x -1

Multiplying both will give us the quadratic equation we are looking for.

(x + 3)(x-1) = x(x -1) + 3(x-1)

= x^2 -x + 3x -3 = x^2 + 2x -3

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Quadrilateral ABCD has the following vertices:
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  yes

Step-by-step explanation:

The figure can be shown to be a parallelogram by showing the sum of endpoints of the diagonals is the same.

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  (0, 6) +(0, -4) = (0, 2) = (3, 5) +(-3, -3) . . . . diagonals bisect each other

If the diagonals of a quadrilateral bisect each other, it is a parallelogram. A parallelogram with a right angle is a rectangle. So, ABCD is a rectangle.

_____

<em>Additional comment</em>

The midpoint of each diagonal is half the sum of the end point coordinates. That is, the midpoints are (0, 2)/2 = (0, 1). Since calculation of the midpoints requires both sums be divided by 2, we can tell the midpoints are the same if the sums are the same.

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Solve the proportional<br> equation below:<br> x/4 = x-6/3
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<h2><u>PROPORTIONAL EQUATION</u></h2><h3>Exercise</h3>

Apply the means-extremes property of proportions: this allows you to cross multiply:

                \boxed{\mathsf{\dfrac{x}{4} = \dfrac{x - 6}{3}}}

\mathsf{\dfrac{x}{4} \searrow \dfrac{x - 6}{3}}      ‏‏‎      ‏‏‎‎      \mathsf{\dfrac{x}{4} \nearrow \dfrac{x-6}{3}}‏‏‎‎

             \boxed{\mathsf{3x = 4(x - 6)}}

Apply the distributive property:

\mathsf{3x = 4(x-6)}

\mathsf{3x = 4(x) - 4(6)}

\mathsf{3x = 4x - 24}

Add 24 to both sides:

\mathsf{3x + 24 = 4x - 24 + 24}

\mathsf{3x + 24 = 4x}

Substract 3x to both sides

\mathsf{3x - 3x + 24 = 4x - 3x}

\mathsf{24 = 4x - 3x}

\large{\boxed{\mathsf{24 = x}}}

‎      ‏‏‎

<h3><u>Answer</u>. The value of x = 24.</h3>

‎      ‏‏‎

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