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3 years ago

If a formula had addition, division, exponents, and brackets which would the spreadsheet calculate first?

Mathematics

2 answers:

barxatty [35]3 years ago

3 0

It would calculate brackets first.

Rashid [163]3 years ago

3 0

H̲̅ᴇ̲̅ʏ̲̅!̲̅ Hope that I can help!

I went into a spreadsheet and figured it out. They calculate the brackets first.

If you were helped by my answer, remember that I worked really hard on it. Please click the [ ♥ ᴛʜᴀɴᴋs ] button below and give me a rating of ★★★★★ to show your appreciation.

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Gennadij [26K]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Let's solve for x :

$\sqrt{x - 2} - x = - 2$

$\sqrt{x - 2} = x - 2$

$1 = \dfrac{x - 2}{ \sqrt{x - 2} }$

$1 = \sqrt{x - 2}$

$x - 2 = 1$

$x = 3$

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3 years ago

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inn [45]

Answer:

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Step-by-step explanation:T-T X_X X_X

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2 years ago

Read 2 more answers

Help please, put how you found it out if you can too !

earnstyle [38]

Answer:

104 degrees

Step-by-step explanation:

180-(180-(180-(25+85)+65)+31)

7 0

2 years ago

Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap

bazaltina [42]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)$

$A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

<em>The circumference of a quarter of circle is equal to</em>

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

6 0

3 years ago

chegg porter averages 21 points per basketball game with a standard deviation of 4.5 points. suppose porter's points per basketb

romanna [79]

Chegg porter averages 21 points per basketball
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8 0

1 year ago