<span>Area is base times height, so 9h = 36, h = 4
sine of base angle will be 4/6 = 2/3
So, the answer is A) 2/3
Hope this helps!
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Answer:
A. △ABC and △JKL are similar.
Step-by-step explanation:
Since three angles of one triangle are congruent to three corresponding angles of the other triangle, the triangles are either congruent or similar. Since the side of one triangle is twice the length of the corresponding side of the other triangle, then the triangles are not congruent, but they are similar.
A. △ABC and △JKL are similar.
Step-by-step explanation:
use formula
(-b+√b2-4ac)/2a
a=3, b=2 , c=5
(-2+√4-4×3×5)/2×3
(-2+√-56)/6
(-2+2√-14)/6
(-2 +2√14i)/6
We need an equation for this, theres no 'formula' for doing this (ignoring the quadratic formula, as that is a long-winded way of factorising a quadratic equation)
You can do this using synthetic division, which is the easiest way. If x - 2 = 0, then x = 2. That 2 will go outside the "box" and the leading coefficients of the terms in the polynomial will go inside the "box". 2 (1 -3 -10 24). Bring down the first number, the
1. Multiply that 1 by the 2 to get 2. Put that 2 up under the -3 and add to get
-1. Multiply that -1 by the 2 to get -2. Put that =-2 up under the -10 and add to get
-12. Multiply that -12 by the 2 to get -24. Put the -24 up under the 24 and add to get 0. That means that x - 2 is a factor of the polynomial. What's left, the bolded numbers, are the coefficients of a new polynomial that is one degree less than the polynomial you started with. In other words, when we divide your polynomial by x-2, you get

.