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ch4aika [34]
3 years ago
15

How do I do this I need a little help

Mathematics
2 answers:
dangina [55]3 years ago
8 0

Answer:

B

Step-by-step explanation:

the decay will cause loss so it's the function B

marysya [2.9K]3 years ago
3 0

Answer:

B

Step-by-step explanation:

trust

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Can u answer this plz​
Rzqust [24]

Answer:

The answer is 14 :)

Step-by-step explanation:

6 0
3 years ago
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the sum of two numbers is 57. If the larger number is three less than twice the smaller number find both numbers
bearhunter [10]

Answer:

Step-by-step explanation:

x = larger number, y = smaller number

x + y = 57

x = 2y - 3

2y - 3 + y = 57

3y - 3 = 57

3y = 57 + 3

3y = 60

y = 60/3

y = 20 <=== the smaller number

x = 2y - 3

x = 2(20) - 3

x = 40 - 3

x = 37 <=== the larger number

3 0
3 years ago
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In this picture, m∠AOC = 65° and m∠COD = (2x + 4)°. If ∠AOC and ∠COD are complementary angles, then what is the value of x?
dmitriy555 [2]

Answer:

I think it's C hope it helps you

4 0
3 years ago
The probability that a single radar station will detect an enemy plane is 0.65.
taurus [48]

Answer:

a) We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

b) If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

Step-by-step explanation:

For each station, there are two two possible outcomes. Either they detected the enemy plane, or they do not. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

The probability that a single radar station will detect an enemy plane is 0.65. This means that n = 0.65.

(a) How many such stations are required to be 98% certain that an enemy plane flying over will be detected by at least one station?

This is the value of n for which P(X = 0) \leq 0.02.

n = 1.

P(X = 0) = C_{1,0}.(0.65)^{0}.(0.35)^{1} = 0.35

n = 2

P(X = 0) = C_{2,0}.(0.65)^{0}.(0.35)^{2} = 0.1225

n = 3

P(X = 0) = C_{3,0}.(0.65)^{0}.(0.35)^{3} = 0.0429

n = 4

P(X = 0) = C_{4,0}.(0.65)^{0}.(0.35)^{4} = 0.015

We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

(b) If seven stations are in use, what is the expected number of stations that will detect an enemy plane?

The expected number of sucesses of a binomial variable is given by:

E(x) = np

So when n = 7

E(x) = 7*(0.65) = 4.55

If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

6 0
3 years ago
The line parallel to x-3y=-12 that passes through (-3,4)
gulaghasi [49]
X-3y=12
3y=x-12
y=1/3x-4
parallel means same gradient, which is 1/3.
Use formula y-y1=m(x-x1), m=gradient and y1 is y coordinate of point and x1 is x coordinate of point.
y-4=1/3[x-(-3)]
y-4=x/3+1
y=x/3+5
4 0
4 years ago
Read 2 more answers
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