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Lady bird [3.3K]
3 years ago
10

I Reaally Need Help If You Wamt Ill Eve Go Over 100 Points

Mathematics
2 answers:
Pani-rosa [81]3 years ago
5 0
(a) y = 2x + 3
(b) (1,5), (3,3); y = 3x + 3      5 = m1 + b, 3 = m3 + b
(c) coincident i believe, because it is not independent or inconsistent
(d) 2x + 3 = 3x + 3
     (-2x)(-3)  (-2x)(- 3)
0 = -2x
x = 0

hope this helps
Anna35 [415]3 years ago
3 0
A)
side walk 1
slope = (7-3)/(2-0) = 4/2 = 2

b = 3

slope intercept form
y = 2x + 3

b)
sidewalk 2
slope = (3-5)/(3-1) = -2/2 = -1

point slope form equation
y - 5 = -1(x - 1) 

slope intercept form
y - 5 = -1(x - 1)
y - 5 = -x + 1
y = -x + 4 ....slope intercept form

c)
sidewalk1 : y = 2x + 3
sidewalk2: y = -x + 4

2x + 3 = -x + 4
3x = 1
  x = 1/3

y = 2(1/3) + 3
y = 2/3 + 3
y = 3 2/3

solution x = 1/3 and y = 3 2/3
A system of two linear equations can have one solution so it's consistent and exactly 1 solution so<span> it is </span><span>independent
</span>d) you can use this from c)
x = 1/3 and y = 3 2/3

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3 years ago
Find the projection of u onto v<br> URGENT HELP
padilas [110]

Given:

Two vectors are:

u=\left

v=\left

To find:

The projection of u onto v.

Solution:

Magnitude of a vector v=\left is:

|v|=\sqrt{a^2+b^2}

Dot product of two vector v_1=\left and v_2=\left is:

v_1\cdot v_2=a_1a_2+b_1b_2

Formula for projection of u onto v is:

Proj_vu=\dfrac{u\cdot v}{|v|^2}v

Proj_vu=\dfrac{\left \cdot \left }{(\sqrt{2^2+17^2)^2}}\left

Proj_vu=\dfrac{0\cdot 2+6\cdot 17}{4+289}\left

Proj_vu=\dfrac{0+102}{293}\left

On further simplification, we get

Proj_vu=\dfrac{102}{293}\left

Proj_vu=\left

Proj_vu=\left

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LUCKY_DIMON [66]
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