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3 years ago

4. Kristina is allowed to have a friend sleep over every 3rd weekend,

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

3 0

Answer:

Step-by-step explanation:

You must find the least common multiple of their schedules.

The numbers 3 and 2 are their own prime factors, so the least common multiple of 3 and 2 is 6.

Six weekends must pass until they can both have someone over on the same night.

The number line below shows that the first time their sleepovers coincide is Week 6.

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Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

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The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

Hence, the midpoint of the segment is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

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How to change 3 7/8 into an improper fraction

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