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GrogVix [38]
2 years ago
11

Solve for X: -22=-7+3/5x

Mathematics
1 answer:
stira [4]2 years ago
3 0



solution for the problem-

X=-22
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Let F be the function given by f(x)= 2xe^x. Determine the interval(s) on which the graph is concave down.
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Hello,

y=2xe^x
y'=2(e^x+xe^x)=2(x+1)e^x
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x+2 |------------0 +++++++++++
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y''<0 if x<-2
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7 0
3 years ago
PLEASE HELP ON THIS, Find the area of the shape shown below.
aivan3 [116]
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3 years ago
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Solve the equation w+ 2 = for c.
Zielflug [23.3K]
Isn’t it supposed to be a minus sign? For it can be like w-2, w-2 ?
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3 years ago
A chemistry teacher needs to mix a 20% salt solution with an 80% salt solution to make 20 qt of a 40% salt solution. How many qu
Svetlanka [38]

Answer:

  • 6 2/3 qt 80%
  • 13 1/3 qt 20%

Step-by-step explanation:

It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.

__

We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...

  0.80x +0.20(20-x) = 0.40(20)

  0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify

  x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution

  (20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed

The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.

3 0
2 years ago
Decide whether each table could represent a proportional relationship. If the
Ymorist [56]

Answer:

Step-by-step explanation:

If given tables in the picture show the proportional relationship,

Number of wheels (w) ∝ Number of buses (b)

w ∝ b

w = kb

Here, k = proportionality constant

k = \frac{w}{b}

Number of buses (b)           Number wheels (w)             Wheels per bus (\frac{w}{b})

          5                                           30                               \frac{30}{5}=6              

          8                                           48                               \frac{48}{8}=6

         10                                           60                               \frac{60}{10}=6

         15                                           90                               \frac{90}{15}=6

Here, proportionality constant is 6.

Similarly, If number of wheels (w) ∝ Number of train cars (t)

w = kt

Here, k = proportionality constant

k = \frac{w}{t}

Number of train cars(t)          Number of wheels(w)     Wheels per train car (\frac{w}{t})

              20                                        184                           \frac{184}{20}=9.2

              30                                        264                           \frac{264}{30}=8.8

              40                                        344                           \frac{344}{40}=8.6

              50                                        424                           \frac{424}{50}=8.48

Since, ratio of w and t is not constant, relation between number of wheels and number of train cars is not proportional.

5 0
2 years ago
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