Answer:
Minimum < Q1 < Median < Q3< Maximum
Step-by-step explanation:
Given
Minimum, Median, Maximum, Q3 and Q1
<em>See attachment for complete question</em>
Required
Order from least to greatest
In a dataset, the range is:
This implies that, the minimum is the least and the maximum is the highest of the dataset
So, we have:
Minimum < < < < Maximum
The median is the middle item; So, the above becomes
Minimum < < Median < < Maximum
In a dataset, the IQR is:
This implies that:
So, we have:
Minimum < Q1 < Median < Q3< Maximum
Answer:
Step-by-step explanation:
Answer:
a) 18
b) 10
c) x^2 - 4x + 5
d) 4x^2 + 2
Step-by-step explanation:
f(x) = 4x - 2
g(x) = x^2 + 1
a) f(5) = 4(5) - 2 = 20 - 2 = 18.
b) g(-3) = (-3)^2 + 1 = 9 + 1 = 10.
c) g(x - 2)...
g(x - 2) = (x - 2)^2 + 1 = x^2 - 2x - 2x + 4 + 1 = x^2 - 4x + 5.
d) f(g(x)) = f(x^2 + 1) = 4(x^2 + 1) - 2 = 4x^2 + 4 - 2 = 4x^2 + 2.
Hope this helps!
Answer:
The value of n is 2.
Step-by-step explanation:
The total number of people in the choir = 60
Number of women in the choir = 30
Let the number of men in the choir be represented by x, so that;
Number of women = 3x
So that;
3x = 30
x = 
= 10
The number of men in the choir is 10.
the number of children in the choir: the number of men in the choir = n:1
number of children in the choir = 60 - (number of women + number of men)
= 60 - 40
= 20
number of children in the choir = 20
Thus,
the number of children in the choir: the number of men in the choir = 20:10
= 2:1
The value of n is 2.
