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3 years ago

WILL MARK BRAINLIEST Which of the following is not true?

Mathematics

2 answers:

eimsori [14]3 years ago

8 0

Answer:

Option D

Step-by-step explanation:

It should be 250%, not 25%

Hope this helped, have a nice day! :)

blondinia [14]3 years ago

6 0

Answer:

Step-by-step explanation:

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Which phrase describes the algebraic expression 3 x minus 4?

zaharov [31]

Answer:

3x - 4 = -12

Step-by-step explanation:

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2 years ago

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25 POINTS

Semenov [28]

If the slope of AB = CD and BC = AD it's a parallelogram:

Slope of AB = 6+1 / -9+5 = -7/4

CD = -2-5 / 3+1 = -74

These are equal.

BC = 5-6 / -1 +9 = -1/8

AD = -2 +1 / 3+5 = -1/8

These are also equal so it is a parallelogram.

Now to find if the diagonals are perpendicular find the slope of the perpensicular points:

AC = 5 +1 / -1 +5 = 6/4 = 3/2

BD = 6+2 / -9 -3 = 8/-12 = -2/3

Because BD is the reciprocal of AC, this means they are perpendicular.

And because AB is not perpendicular to AD ( AB and AD are not reciprocals) it is a rhombus.

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2 years ago

What fraction of 5 is 1/2

Sphinxa [80]

Answer:

1/10

Step-by-step explanation:

1/2 divided by 5 = 1/10

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2 years ago

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The seller of a property has paid $2,700 in property taxes for the year in advance. The closing date of the sale is December 24

Rashid [163]

The correct answer is a 2700

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2 years ago

Pls help asap whats the local min value of the function below?

shutvik [7]

Answer:

given function has 2 minimums - $\frac{9}{4}$ and $\frac{9}{4}$

Step-by-step explanation:

Step 1. g'(x) = 4x³ - 10x

Step 2. Find find the critical points:

4x³ - 10x = 2x(2x² - 5) = 0

$x_{1}$ = - $\sqrt{\frac{5}{2} }$ , $x_{2}$ = 0 , $x_{3}$ = $\sqrt{\frac{5}{2} }$

Step 3. g'(x) > 0 : - $\sqrt{\frac{5}{2} }$ < x < 0 or x > $\sqrt{\frac{5}{2} }$

g'(x) < 0 : x < - $\sqrt{\frac{5}{2} }$ or 0 < x < $\sqrt{\frac{5}{2} }$

Step 4.

If x ∈ ( - ∞ , - $\sqrt{\frac{5}{2} }$ ) , g(x) is decreasing ;

If x = - $\sqrt{\frac{5}{2} }$ , g(x) has minimum value ;

If x ∈ ( - $\sqrt{\frac{5}{2} }$ , 0 ) , g(x) is increasing ;

If x = 0 , g(x) has maximum value ;

If x ∈ ( 0 , $\sqrt{\frac{5}{2} }$ ) , g(x) is decreasing ;

If x = $\sqrt{\frac{5}{2} }$ , g(x) has minimum value ;

If x ∈ ( $\sqrt{\frac{5}{2} }$ , ∞ ) , g(x) is increasing .

⇒ at ( - $\sqrt{\frac{5}{2} }$ , - $\frac{9}{4}$ ) and at ( $\sqrt{\frac{5}{2} }$ , $\frac{9}{4}$ ) , g(x) reaches its minimum

8 0

3 years ago