Answer:
Amount of money Judy has in her account is
.
Amount of money Tommy has in his account is 
Step-by-step explanation:
To find : Amount of money in Judy account and amount of money in Tommy account:
Solution:
Given:
Judy has $7500 more than a number in her account.
Let the number be 'n'.
So we can say that;
Amount of money in Judy account is equal to 7500 plus number.
framing in equation form we get;
Amount of money in Judy account = 
Hence Amount of money Judy has in her account is
.
Now Given:
Tommy has 6 more than 3 times the amount of money in his bank account than Judy.
So we can say that;
Amount of money in Tommy account is equal to 3 multiplied by Amount of money in Judy account plus 6.
framing in equation form we get;
Amount of money in Tommy account = 
Hence Amount of money Tommy has in his account is
.
Answer:
14 + j = 28
Step-by-step explanation:
I hope this helps :)
Answer:

Step-by-step explanation:
so you already have the formula, which is
![\sqrt[3]{ \frac{3v}{4\pi} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3v%7D%7B4%5Cpi%7D%20%7D%20)
the v represents Volume.
and 3v would be 3×volume.
![\sqrt[3]{ \frac{3 \times 1000}{4 \times \pi} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%201000%7D%7B4%20%5Ctimes%20%5Cpi%7D%20%7D%20)
![\sqrt[3]{ \frac{3000}{12.56637061} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3000%7D%7B12.56637061%7D%20%7D%20)
![\sqrt[3]{238.7324147 }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B238.7324147%20%7D%20)

to the nearest tenth place.

Answer:
m<r =75
PS=2.1 cm
Step-by-step explanation:
they are equal so you should be able to figure it out eventually
You have to make the denominators (bottom numbers) the same via multiplication, it's best to do it to the first number they meet at. that would be fifteen (15)
5×3=15
3×5=15
you then have to multiply the numerators by the respective numbers.
2×3=6
1×5=5
you then subtract the numerators normally
6-5=1
slap back on the denominator
1/15
there's your answer.
(the number you multiply them by isn't the other denominator, it just happens to be the denominators for this equation)