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3 years ago

What is true about MSR?

Mathematics

2 answers:

Zigmanuir [339]3 years ago

8 0

Answer:

Step-by-step explanation:

andre [41]3 years ago

4 0

<span>The correct answer is it must be a right angle.

Explanation<span>:
This is a rhombus, as it is a parallelogram with all congruent sides. In a rhombus, diagonals are perpendicular bisectors of each other; this means that they meet at right angles, so MSR must be a right angle.</span></span>

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Line z has a slope of 2.5 and goes through point (4, 13). Which equation best represents line z?

AnnyKZ [126]

Answer:

y - 13 = (5/2)(x - 4)

Step-by-step explanation:

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3 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :