Please help me with this

Mathematics

1 answer:

Tanya [424]2 years ago

8 0

9514 1404 393

Answer:

51.63 m²

Step-by-step explanation:

The relevant area formulas are ...

A = πr² . . . . . area of a full circle of radius r

A = LW . . . . area of a rectangle of length L and width W

A = 1/2bh . . . area of a triangle with base b and height h

The figure area is the sum of the areas of 1/2 a circle of radius 3 m, a rectangle with base 6 m and height 5 m, and a triangle with base 3 m and height 5 m. Using the above formulas, we find the area to be ...

A = (1/2)(3.14)(3 m)² +(6 m)(5 m) + 1/2(3 m)(5 m)

A = (14.13 +30 +7.5) m² = 51.63 m²

The area of the figure is about 51.63 m².

You might be interested in

Malachy rolls a fair dice 168 times.

baherus [9]

Answer:

28 times

Step-by-step explanation:

On a fair die, the probability of rolling a 6, the only number greater than 5, is 1/6. So in 168 rolls of this die, Malachy can expect a 6 on 1/6 × 168, or 28 times.

8 0

1 year ago

11th grade geometry:

Aliun [14]

Answer:

The perimeter is 72 units and the area is 149 square units.

Step-by-step explanation:

$\triangle SBA$ has coordinates $S(15,-8),B(-2,21)$ and $A(0,0)$

Using the distance formula.........

Length of side $SB = \sqrt{(15+2)^2+(-8-21)^2}= \sqrt{17^2+(-29)^2}= \sqrt{1130}$

Length of side $BA= \sqrt{(-2)^2+(21)^2}= \sqrt{445}$

Length of side $AS =\sqrt{(15)^2+(-8)^2}=\sqrt{289}=17$

So, the perimeter of the triangle will be: $(SB+BA+AS)= \sqrt{1130}+ \sqrt{445}+17 =71.71... \approx 72$ units. (Rounded to the nearest unit)

The height of the triangle for the corresponding base $SB$ is 8.89 units.

Formula for the Area of triangle, $A= \frac{1}{2}(base\times height)$

So, the area of the $\triangle SBA$ will be: $\frac{1}{2}(\sqrt{1130}\times 8.89)= 149.42... \approx 149$ square units. (Rounded to the nearest unit)