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WITCHER [35]
3 years ago
11

Please help me with this

Mathematics
1 answer:
Tanya [424]3 years ago
8 0

9514 1404 393

Answer:

  51.63 m²

Step-by-step explanation:

The relevant area formulas are ...

  A = πr² . . . . . area of a full circle of radius r

  A = LW . . . .  area of a rectangle of length L and width W

  A = 1/2bh . . . area of a triangle with base b and height h

__

The figure area is the sum of the areas of 1/2 a circle of radius 3 m, a rectangle with base 6 m and height 5 m, and a triangle with base 3 m and height 5 m. Using the above formulas, we find the area to be ...

  A = (1/2)(3.14)(3 m)² +(6 m)(5 m) + 1/2(3 m)(5 m)

  A = (14.13 +30 +7.5) m² = 51.63 m²

The area of the figure is about 51.63 m².

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Karolina [17]

Answer:

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3 0
3 years ago
The owner of a manufacturing plant employs eighty people. As part of their personnel file, she asked each one to record to the n
Mashcka [7]

Answer:

The variance of the given data is 106.9667

Step-by-step explanation:

The variance, S² of a sample is given by the expression;

S^2 = \dfrac{\sum \left (x_{i}-\bar{x}  \right )^{2}}{n-1}

Where:

x_{i} = One of the observations

\bar{x} = The mean of the observations

n = Number in the sample = 6

The mean = Σx_{i}/n = (26  + 32 + 29  + 16  + 45  + 19 )/6 = 167/6 = 27.833

Therefore, we have;

S² = ((26 - 27.833)²+(32 - 27.833)²+(29 - 27.833)²+(16 - 27.833)²+(45 - 27.833)²+(19 - 27.833)²)/(6 - 1) = 106.9667.

3 0
3 years ago
A chemist is mixing two solutions, solution A and solution B. Solution A is 15% water and solution Bis 20% water. She already ha
LiRa [457]

Answer:

15 ml

Step-by-step explanation:

We are told

Solution A = 15% of water

Solution B = 20% of water

Let's assume, the entire solution = 100ml

We are told that in the beaker we have 10 ml of Solution A already

Mathematically,

100 ml = 15%

10 ml = X

100ml × X = 15 × 10

X = 150/ 100

X = 1.5%

Hence in the beaker, we have 1.5% of water from Solution A

We are asked to find how many ml of solution B must be added to make the solution have 18% of water

Let y = number of ml of solution B

Hence

10 ml × 15%(0.15) = 1.5 ml of water - Equation 1

y ml × 20%( 0.20) = 0.20y ml of water ...... Equation 2

Add up the above equation

10ml + y ml ×18% (0.18) = 1.5 + 0.20y

(10 + y)(0.18) = 1.5 + 0.20y

1.8 + 0.18y = 1.5 + 0.20y

Collect like terms

1.8 - 1.5  = 0.20y - 0.18y

0.3 = 0.02y

y = 0.3/0.02

y = 15ml                              

Therefore,15mL of solution B must be added to the beaker in order to create a mixture that is 18% water

                     

4 0
3 years ago
Can u solve this puzzle?
finlep [7]

Answer:

i dont think so sorry

4 0
3 years ago
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