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Vika [28.1K]
2 years ago
13

Lizzie has already written 120 words of an essay. She writes 5 words per minute. Write an expression to represent the total numb

er of words she has written after her writing session today. Let m represent the number of minutes passed during today’s session.
Mathematics
1 answer:
Wittaler [7]2 years ago
4 0

Answer:

The Expression: 120 + 5m

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3x - y = -10<br> -8x - y = 23
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(x,y)=(0,-23)

Step-by-step explanation:

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Jim has a home loan and a car loan. He defaults on his home loan after a year of making payments on time.However, he continues t
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Read 2 more answers
Help ASAP! And explain!
stich3 [128]

Answer:

Option (2)

Step-by-step explanation:

Given:

AC is an angle bisector of ∠DAB and ∠DAB

m∠BCA ≅ m∠DCA

m∠BAC ≅ m∠DAC

To Prove:

ΔABC ≅ ΔADC

Solution:

               Statements                                  Reasons

1). m∠BCA ≅ m∠DCA                            1). Given

2). m∠BAC ≅ m∠DAC                           2). Given

3). AC ≅ AC                                            3). Reflexive property

4). ΔABC ≅ ΔADC                                 4). ASA property of congruence

Therefore, Option (2) will be the correct option.

4 0
2 years ago
Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
2 years ago
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