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3 years ago

HELP ME PLEASE! I’m so dumb and don’t understand this help me!!!

Mathematics

1 answer:

Verdich [7]3 years ago

3 0

First, simplify the first two terms: 3sqrt(x) - 2sqrt(x). This reduces to sqrt(x).

Next, add 4sqrt(x) to this 1sqrt(x); the sum and answer to this question is 5sqrt(x).

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The formula for the volume of a sphere is V= 4/3 pi r cubed. what is the formula solved for r

Reil [10]

V=4/3π r^3

(3/4)V=π r^3

3V/4π = r^3

third root√(3V/4π)

<span><span>Hope this helps!
</span>and May the Force Be With You
</span><span>
-Jabba</span>

6 0

3 years ago

Read 2 more answers

Select all the rates equivalent to the rate 3/4 cup per pound

Artemon [7]

Answer:

Step-by-step explanation:

Multiply the decimal by 100 and write the result with the percentage sign: 0.75 × 100 = 75%.

3 0

2 years ago

How to increase 42kg by 3%

lbvjy [14]

Multiply .03 by 42

.03×42=1.26

1.26kg + 42kg= 43.26

Answer: 43.26kg

4 0

2 years ago

1. How many variables are involved in the chi-square test?

GarryVolchara [31]

The result of the respective questions are:

This chi-square test only takes into consideration one variable.
The type of chi-square test this is is a Goodness of Fit
df= 3
NO

<h3>How many variables are involved in the chi-square test?</h3>

This chi-square test only takes into consideration one variable.

The type of chi-square test this is, is a Goodness of Fit

To test the hypothesis, we must determine whether the actual data conform to the assumed distribution.

The "Goodness-of-Fit" test is a statistical hypothesis test that determines how well the data that was seen resembles the data that was predicted.

Parameter

n = 4

Therefore

Degrees of freedom

df= n - 1

df= 4 - 1

df= 3

In conclusion

Parameters

$\alpha = 0.05$

df = 3

Hence

Critical value = 7.814728

Test statistic = 6.6

Test statistic < Critical value, .

NO, the result of this test is not statistically significant.

Read more about Probability

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3 0

2 years ago

I have the question in a screengrab. Thank you, whoever helps me.

nata0808 [166]

To simplify

$\sqrt[4]{\dfrac{24x^6y}{128x^4y^5}}$

we need to use the fact that

$\sqrt[4]{x^4}=|x|$

Why the absolute value? It's because $(-x)^4=(-1)^4x^4=x^4$ .

We start by rewriting as

$\sqrt[4]{\dfrac{2^23x^6y}{2^6x^4y^5}}$

$\sqrt[4]{\dfrac{2^23x^4x^2y}{2^42^2x^4y^4y}}$

Since $x\neq0$ , we have $\dfrac xx=1$ , and the above reduces to

$\sqrt[4]{\dfrac{3x^2y}{2^4y^4y}}$

Then we pull out any 4th powers under the radical, and simplify everything we can:

$\dfrac1{\sqrt[4]{2^4y^4}}\sqrt[4]{\dfrac{3x^2y}{y}}$

$\dfrac1{|2y|}\sqrt[4]{3x^2}$

where $y>0$ allows us to write $\dfrac yy=1$ , and this also means that $|y|=y$ . So we end up with

$\dfrac{\sqrt[4]{3x^2}}{2y}$

making the last option the correct answer.

7 0

3 years ago