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sdas [7]
3 years ago
6

Your reading material points out that items such as pens stickers and mugs May often be purchased by retailers at a discount

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
7 0
The answer is C. 50%.
DENIUS [597]3 years ago
7 0

Answer:

Answer is D, 500% as stated in reading material.

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PLEASE HELP ME ASAP!! WILL MARK BRAINLIST
Svet_ta [14]

Answer:

for second box 8. for third box 64 to the power 1/3. for fourth box 1 . and for fifth box 64/512 for sixth box 1/64

8 0
3 years ago
A certain 32 cm spring will stretch (in cm) one-half the weight (in kg) attached to it. How long wilt the spring be if a 26 kg w
Bond [772]
67 I think or 32! Lol
8 0
3 years ago
Need a little help. If anyone knows and would like to answer, I would highly appreciate that :)
jonny [76]
9x+4=5x+20
——————
9x-5x=20-4
—————-
4x=16
————-
X=4
————
My deepest apologies if my answer turned out to be wrong but i tried my best so best of wishes!!
8 0
3 years ago
If we assume the population of Grand Rapids is growing at a rate of approximately 4% per decade, we can model the population fun
saw5 [17]

Answer:

The average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ]  are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

Step-by-step explanation:

The given function is

P(t)=181843(1.04)^{(\frac{t}{10})}

where, P(t) is population after t years.

At t=5,

P(5)=181843(1.04)^{(\frac{5}{10})}=185444.20

At t=6,

P(6)=181843(1.04)^{(\frac{6}{10})}=186172.95

At t=7,

P(7)=181843(1.04)^{(\frac{7}{10})}=186904.57

At t=8,

P(8)=181843(1.04)^{(\frac{8}{10})}=187639.06

At t=9,

P(9)=181843(1.04)^{(\frac{9}{10})}=188376.44

At t=10,

P(10)=181843(1.04)^{(\frac{10}{10})}=189116.72

The rate of change of P(t) on the interval [x_1,x_2] is

m=\frac{P(x_2)-P(x_1)}{x_2-x_1}

Using the above formula, the average rate of change of the population on the intervals [ 5 , 10 ] is

m=\frac{P(10)-P(5)}{10-5}=\frac{189116.72-185444.20}{5}=734.504

The average rate of change of the population on the intervals [ 5 , 9 ] is

m=\frac{P(9)-P(5)}{9-5}=\frac{188376.44-185444.20}{4}=733.06

The average rate of change of the population on the intervals [ 5 , 8 ] is

m=\frac{P(8)-P(5)}{8-5}=\frac{187639.06-185444.20}{3}=731.62

The average rate of change of the population on the intervals [ 5 , 7 ] is

m=\frac{P(7)-P(5)}{7-5}=\frac{186904.57-185444.20}{2}=730.185

The average rate of change of the population on the intervals [ 5 , 6 ] is

m=\frac{P(6)-P(5)}{6-5}=\frac{186172.95-185444.20}{1}=728.75

Therefore the average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ]  are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

7 0
4 years ago
A bag contains 12 red, 30 blue, 20 green, 10 yellow, and 8 black marbles. Nancy chooses 1 marble from the bag. What is the proba
saul85 [17]

Answer:

5/8

Step-by-step explanation:

12+30+20+10 +8 =80 total marbles

12+30+8=50 red blue and black

50/80

5/8

6 0
4 years ago
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