Find the arc length of a semi circle of 12

Please find which quadratic equation matches the graph with work attached

lesya [120]

Answer:

C

Step-by-step explanation:

Firstly, we know that the function must be negative due to its shape. This means that the answer cannot be B

Next we can use the equation $x=\frac{-b}{2a}$ that is used in order to find the vertex of the parabola.

A)

$f(x)=-x^2+6x+7\\a=-1,b=6,c=7\\\\x=\frac{-6}{-2} \\x=3$

As the vertex is at x=3 on the graph, this one could be a contender.

C)

$f(x)=-x^2+6x-7\\a=-1,b=6, c=-7\\\\x=\frac{-6}{-2} \\\\x=3$

This also could be the equation

D)

$f(x)=-x^2-6x-7\\\\a=-1, b=-6, c=-7\\\\x=\frac{6}{-2} \\\\x=-3$

This rules option D out.

For this last step, we can look at where the zeroes would be for each equation. (These values are irrational, so we cannot look at specific number)

A)

$f(x)=-(x^2-6x-7)$

As this equation has a negative value for c, this means that one zero must be positive and the other must be negative.

This means that option A can be ruled out

C)

$f(x)=-(x^2-6x+7)$

As this equation has a positive value for c, this means that both of the zeroes must be positive. This means that it is the only one that fits all of the criteria.

7 0

3 years ago

The area of the rectangle<br> shown is 54 square units.<br> What is its perimeter

Ipatiy [6.2K]

Answer:

perimeter of a square= 4 times square root of area

$4 \sqrt{54} = 29.39$

6 0

4 years ago

What is the average rate of change of the function g(x) = 3(2x) - 6 over the interval 0<=x<=3? Show all work.

Tems11 [23]

The only thing you need to do is to plug in x to get y.hope this helps if it does please mark brainliest

4 0

3 years ago

At what value of x does the minimum or maximum occur for the function below? f(x) = 8(x + 8)2 + 9 A. maximum at x = 9 B. minimum

WINSTONCH [101]

$8 {(x + 8)}^{2} + 9 \geqslant 9 \: ( {(x + 8)}^{2} \geqslant 0) \\ \Leftrightarrow x + 8 = 0\Leftrightarrow x = - 8 \\ \Rightarrow D.\: Minimum\: at\: x=-8$