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densk [106]
3 years ago
5

A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pul

ling out an orange candy is 1 over 9, and the probability of randomly pulling out a strawberry candy is 3 over 9, what is the probability of randomly pulling out a pineapple candy?
Mathematics
2 answers:
adelina 88 [10]3 years ago
7 0
To find this add 3 and 1 together.  This gives you 4.  Then, you subtract 4 from 9.  The answer is 5.  Therefore, the probability to pull out a pineapple candy would be 5/9.
lapo4ka [179]3 years ago
5 0
<h2>Answer:</h2>

The probability of randomly pulling out a pineapple candy is:

                  \dfrac{5}{9}

<h2>Step-by-step explanation:</h2>

There are three flavors in a ice cream namely:

orange, strawberry, and pineapple.

We know that for any three events in a single experiment the sum of the probability of three events is equal to 1.

i.e. if A, B and C are three events and P denotes the probability of an event then:

         P(A)+P(B)+P(C)=1

Here let A= flavor is orange

B= flavor is strawberry

and  C= flavor is pineapple.

and we have:

P(A)=\dfrac{1}{9},\ P(B)=\dfrac{3}{9}

Hence, we have:

\dfrac{1}{9}+\dfrac{3}{9}+P(C)=1\\\\\\i.e.\\\\\\\dfrac{4}{9}+P(C)=1\\\\\\i.e.\\\\\\P(C)=1-\dfrac{4}{9}\\\\\\i.e.\\\\\\P(C)=\dfrac{9-4}{9}\\\\i.e.\\\\P(C)=\dfrac{5}{9}

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Answer:

Option (4)

Step-by-step explanation:

By the property of exterior angle of a triangle,

"Exterior angle of a triangle is equal to the sum of two opposite interior angles."

In the triangle ABC,

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m∠ACD = m∠BAC + m∠ABC

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Therefore, Option (4) will be the correct option.

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Step-by-step explanation:

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Step-by-step explanation:

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Ms.Smith has 28 sixth graders and 42 seventh graders for math. If she wants to break the two grades into identical groups withou
Zinaida [17]
Add the 28 and 42
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4 0
3 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

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3 years ago
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