Question

A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is 1 over 9, and the probability of randomly pulling out a strawberry candy is 3 over 9, what is the probability of randomly pulling out a pineapple candy?

Answer 1

To find this add 3 and 1 together.  This gives you 4.  Then, you subtract 4 from 9.  The answer is 5.  Therefore, the probability to pull out a pineapple candy would be 5/9.

Answer 2

Answer:

The probability of randomly pulling out a pineapple candy is:

                  $\dfrac{5}{9}$

Step-by-step explanation:

There are three flavors in a ice cream namely:

orange, strawberry, and pineapple.

We know that for any three events in a single experiment the sum of the probability of three events is equal to 1.

i.e. if A, B and C are three events and P denotes the probability of an event then:

         P(A)+P(B)+P(C)=1

Here let A= flavor is orange

B= flavor is strawberry

and  C= flavor is pineapple.

and we have:

$P(A)=\dfrac{1}{9},\ P(B)=\dfrac{3}{9}$

Hence, we have:

$\dfrac{1}{9}+\dfrac{3}{9}+P(C)=1\\\\\\i.e.\\\\\\\dfrac{4}{9}+P(C)=1\\\\\\i.e.\\\\\\P(C)=1-\dfrac{4}{9}\\\\\\i.e.\\\\\\P(C)=\dfrac{9-4}{9}\\\\i.e.\\\\P(C)=\dfrac{5}{9}$