Answer:
combines genes from organisms of different species in a lab
Explanation:
Recombinant DNA technology involves the process of joining the genes (DNA) of different multiple species in order to insert into another organism (host). Recombinant DNA technology has many applications in genetic engineering. 
One example of Recombinant DNA is the synthesis of Insulin in bacteria cell where a human insulin gene is first inserted into a plasmid vector, then inserted into a bacterial cell that uses its expression abilities to transcribe and translate the gene into INSULIN protein.
This procedure is usually conducted in a laboratory with the use of certain laboratory equipments. 
 
        
             
        
        
        
Explanation:
 photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy. During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds.
photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy. During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds.
 
        
                    
             
        
        
        
4 cells will result. Each cell will have 20 Chromatids which is half a chromosome. once sexual reproduction takes place, these 20 chromatids will match with those from the other parent cell to form chromosomes 
        
             
        
        
        
Answer:
we will know that the allelic frequencies are for R 0.95 and r 0.05
Explanation:
We know that the population is in Hardy-Winberg equilibrium, we deduce the following formula:
p + q = 1
p2 + 2pq + q2 = 1
data
R: red flower allele
r: allele blor blanca
p would be equal to the allelic frequency R
q will be equal to the frequency allelic r
2p = RR
2q = rr
2pq = Rr
If there are 25 white flowers in 1000 plants, their frequency will be:
2pq frequency of the Rr genotype
white flower = 25/10000 = 0.0025 = rr = 2q = 0.0025
we deduce that q is equal to 0.05
we replace the data with the previous formula
p + q = 1
p = 1-0.05
we get as a result
  p = 0.95
if p = 0.95 and q = 0.05
we will know that the allelic frequencies are for R 0.95 and r 0.05