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sweet-ann [11.9K]
3 years ago
13

Tamara practiced piano for 70 minutes on Tuesday. That is 7 times as long as she practiced on Monday. How long did she practice

on Monday . Draw an array to represent the problem
Mathematics
2 answers:
Feliz [49]3 years ago
7 0
70 divided by 7 equals 10.  

Tamara practiced the piano for 10 minutes on Monday.  <span />
Sergeu [11.5K]3 years ago
5 0
If she practiced 70 minutes on Tuesday and and 70 is 7 times as much as she practiced on Monday then you would use the equation 70/7 (70 divided by 7) So the answer would be 10 
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m_a_m_a [10]

Answer:

7

Step-by-step explanation:

The average rate of change of f(x) in the close interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [2, 5 ]

f(b) = f(5) = 2(5)² - 7(5) = 50 - 35 = 15

f(a) = f(2) = 2(2)² - 7(2) = 8 - 14 = - 6, thus

average rate of change = \frac{15-(-6)}{5-2} = \frac{21}{3} = 7

3 0
3 years ago
Which angle has a sine of -1/2 and a cosine of -√3/2
Sergeeva-Olga [200]
\sin x=-\dfrac{1}{2} < 0\\\\\cos x=-\dfrac{\sqrt3}{2} < 0\\\\therefore\ x\in(180^o;\ 270^o)

\text{We know:}\ \tan x=\dfrac{\sin x}{\cos x}\\\\\text{therefore:}\ \tan x=\dfrac{-\frac{1}{2}}{-\frac{\sqrt3}{2}}=\dfrac{1}{2}\cdot\dfrac{2}{\sqrt3}=\dfrac{1}{\sqrt3}\cdot\dfrac{\sqrt3}{\sqrt3}=\dfrac{\sqrt3}{3}

\tan x=\dfrac{\sqrt3}{3}\Rightarrow x=30^o+180^o\cdot k;\ k\in\mathbb{Z}

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8 0
3 years ago
Help me to solve this please​
scZoUnD [109]

Answer:

-4/9

Step-by-step explanation:

We first calculate the first bracket.

[2/3-(-4/9)]

= (2/3+4/9) (we cancel out the negatives)

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= 10/9

Then we convert -2 1/2 into an improper fraction.

-2 1/2

= -5/2

Finally we calculate the division by swapping the numerator and denominator of -5/2.

10/9 / -5/2

= 10/9 * -2/5

= -20/45

= -4/9 (simplify the terms)

3 0
3 years ago
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Dafna1 [17]
0.075, 0.75, 3, 4, 20
8 0
3 years ago
Read 2 more answers
WHAT IS THE DECIMAL FORM FOR 7 x 10 + 9 x (1/10) + 2 x (1/100) + 5 x (1/000)
max2010maxim [7]

Answer:

70.925 I believe

Step-by-step explanation:

6 0
3 years ago
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