Question

A line has a slope of -3/5. Which ordered pairs could be points on a parallel line? Check all that apply.

Answer 1

(-2,1) and (3, -2) you can find this by calculating y2-y1 over x2-x1

Answer 2

Answer:

Option A and D are correct

(–8, 8) and (2, 2),   (–2, 1) and (3, –2)

Step-by-step explanation:

Parallel line:

In parallel lines, the two lines have the same slope and will never intersects.

Using the slope formula:

$\text{Slope} = \frac{y_2-y_1}{x_2-x_1}$            ....[1]

As per the statement:

A line has a slope of -3/5.

We have to find which ordered pairs could be points on a parallel line.

A.

(–8, 8) and (2, 2)

Substitute in [1] we have;

$\text{Slope} = \frac{2-8}{2-(-8)}$

⇒$\text{Slope} = \frac{-6}{10}= -\frac{3}{5}$

Similarly for:

B.

(–5, –1) and (0, 2)

Substitute in [1] we have;

$\text{Slope} = \frac{2-(-1)}{0-(-5)}$

⇒$\text{Slope} = \frac{3}{5}= \frac{3}{5}$

C.

(–3, 6) and (6, –9)

Substitute in [1] we have;

$\text{Slope} = \frac{-9-6}{6-(-3)}$

⇒$\text{Slope} = \frac{-15}{9}=- \frac{5}{3}$

D.

(–2, 1) and (3, –2)

Substitute in [1] we have;

$\text{Slope} = \frac{-2-1}{3-(-2)}$

⇒$\text{Slope} = \frac{-3}{5}= -\frac{3}{5}$

E.

(0, 2) and (5, 5)

Substitute in [1] we have;

$\text{Slope} = \frac{5-2}{5-0}$

⇒$\text{Slope} = \frac{3}{5}=\frac{3}{5}$

Therefore, the ordered pairs could be points on a parallel line are:

(–8, 8) and (2, 2)

(–2, 1) and (3, –2)