First of all let x-1=0
x=1
Therefore,
P(x)=2x^4+4x^3-7x^2-kx+9
P(1)=2(1)^4+4(1)^3-7(1)^2-k(1)+9
2(1)+4(1)-7(1)-k+9=0
2+4-7-k+9=0
15-7-k=0
8-k=0
-k=-8
Therefore,k=8
I dunno if this is right or not but x=20.
Step-by-step explanation:
total students=99
finished entering marks =9\11
let the entered number be x
now,
"x=9\11×99
x=9×9
x=81
again,
99-81=18
the remaining number of students is 18
Answer:
the first one
Step-by-step explanation:
multiply by 4 subtract 2
