Question

the radius of the aluminum atom is 143pm. the radius of the aluminum atom is 54pm. by what percentage did the radius change as the ion formed?

Answer 1

Answer:

There was 62.23% change in radius as the ion formed.

Step-by-step explanation:

Given

Radius of Aluminium $(Al)$ atom  = 143 pm

Radius of Aluminium $(Al^{3+})$ atom  = 54 pm

Change is the radius =  Radius of Aluminium $(Al)$ atom - Radius of Aluminium $(Al^{3+})$ atom = 143 -54 = 89

Now to find % Change is the radius we will divide Change is the radius by Radius of Aluminium $(Al)$ atom and multiply by 100 we get

% Change is the radius = $\frac{\textrm{Change is the radius}}{\textrm{Radius of Aluminium (Al) atom}} \times 100 = \frac{89}{143}\times100= 62.23\%$

Hence there was 62.23% change in radius as the ion formed.