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charle [14.2K]
3 years ago
9

the radius of the aluminum atom is 143pm. the radius of the aluminum atom is 54pm. by what percentage did the radius change as t

he ion formed?

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
4 0

Answer:

There was 62.23% change in radius as the ion formed.

Step-by-step explanation:

Given

Radius of Aluminium (Al) atom  = 143 pm

Radius of Aluminium (Al^{3+}) atom  = 54 pm

Change is the radius =  Radius of Aluminium (Al) atom - Radius of Aluminium (Al^{3+}) atom = 143 -54 = 89

Now to find % Change is the radius we will divide Change is the radius by Radius of Aluminium (Al) atom and multiply by 100 we get

% Change is the radius = \frac{\textrm{Change is the radius}}{\textrm{Radius of Aluminium (Al) atom}} \times 100 = \frac{89}{143}\times100= 62.23\%

Hence there was 62.23% change in radius as the ion formed.

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