Creating box plots<br>Problem<br>Which data set could be represented by the box plot shown below?

Andrew, a fitness coach for a large oil company, would like to test if his exercise program has increased muscle mass in his cli

vodka [1.7K]

Answer:

Reject $H_0$

The test statistic is in the rejection region

Step-by-step explanation:

Since we want to test if the mean predicted by the coach is greater than the mean of the null hypothesis $\bf H_0$ , this is a right-tailed test. It means that, in order to reject $\bf H_0$ , the test statistic must fall to the right (greater than) of the critical value $\bf z_0$

Given that 2.56 > 1.65 then we reject $\bf H_0$

<em>The test statistic is in the rejection region (greater than 1.65) </em>

4 0

3 years ago

The expression 10a+6c gives the cost (in dollars) for a adults and c children to eat at a buffet restaurant.

katrin [286]

Answer:

Answer: The total cost is assuming the cost for 1 adult is and the cost for 1 child is

Step-by-step explanation:

5 0

3 years ago

(1 point) suppose that the trace of a 2×22×2 matrix aa is tr(a)=−4tr(a)=−4, and the determinant is det(a)=0det(a)=0. find the ei

DedPeter [7]

Suppose

$\mathbf A=\begin{bmatrix}a&b\\c&d\end{cases}$

with $\mathrm{tr}\,\mathbf A=a+d=-4$ and $\det\mathbf A=ad-bc=0$ . We can find the eigenvalues of $\mathbf A$ in the usual way, by taking the determinant of $\mathbf A-\lambda\mathbf I$ and setting it equal to 0.

$\begin{vmatrix}a-\lambda&b\\c&d-\lambda\end{vmatrix}=(a-\lambda)(d-\lambda)-bc=\lambda^2-(a+d)\lambda+(ad-bc)$

and we observe that the characteristic polynomial has linear coefficient $-\mathrm{tr}\,\mathbf A$ and constant coefficient $\det\mathbf A$ . Thus in this case we have the characteristic polynomial equation,

$\lambda^2+4\lambda=\lambda(\lambda+4)=0\implies\lambda_1=0,\lambda_2=-4$

4 0

3 years ago

A given line has the equation 10x 2y=−2 . what is the equation, in slope-intercept form, of the line that is parallel to the giv

aivan3 [116]

The equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 1

<h3>Equation of a line</h3>

A line is the distance between two points

Given the equation of a line expressed as 10x + 2y = -2. Determine the slope

2y = -10x -2

y = -5x - 1

Slope of the line is -5

The equation of a line in point-slope form is y - y1 = m(x-x1)

Substitute the point and the slope of the parallel line

y - 12 = -5(x - 0)
y - 12 = -5x
y = -5x + 12

Hence the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 12

Learn more on equation of a line here: brainly.com/question/13763238

#SPJ4

3 0

2 years ago

Factor the following using the difference of squares method

Bond [772]

Answer:

a)

${x}^{2} - 16 \\ = {x}^{2} - {4}^{2} \\ = (x + 4)(x - 4)$

b)

${9y}^{2} - 25 \\ = {(3y)}^{2} - {5}^{2} \\ = (3y + 5)(3y - 5)$

here is the answer hope that will help you

6 0

3 years ago

Creating box plotsProblemWhich data set could be represented by the box plot shown below?