Answer:
He can make only one batch of cookies.
Step-by-step explanation:
Just by mental math you can say he can make maximum one batch of cookies.
Total sugar = 10 cups
sugar used for lemonade = 2 cups
leftover sugar = 8 cups
For 1 batch of cookie sugar needed = 11/2
which means 5 and 1/2 cups
And he's just left with 8 cups of sugar after lemonade
8 - 5 1/2 = 2 1/2 which is not enough for 2nd batch
That means the maximum number of cookies batches is 1.
Another way to solve it by inequality:
2+Il/2 X <u><</u> 10
11/2 X <u><</u> 8
11X <u><</u> 16
X <u><</u> 1 6/11
So he can make only one batch of cookies.
Answer:
parallelogram
Step-by-step explanation:
slope of DE = (4-7) / (-4 - 2) = 1/2
slope of FT = (-3 - -6) / (11-5) = 1/2
DE // FT
slope of EF = (-6 - 4) / (5 - -4) = - 10/9
slope of DT = (-3 - 7) / (11 - 2) = - 10/9
EF // DT
Answer:
⅛
Step-by-step explanation:
P(H&H&H) = ½ × ½ × ½ = ⅛
Answer:
For first lamp ; The resultant probability is 0.703
For both lamps; The resultant probability is 0.3614
Step-by-step explanation:
Let X be the lifetime hours of two bulbs
X∼exp(1/1400)
f(x)=1/1400e−1/1400x
P(X<x)=1−e−1/1400x
X∼exp(1/1400)
f(x)=1/1400 e−1/1400x
P(X<x)=1−e−1/1400x
The probability that both of the lamp bulbs fail within 1700 hours is calculated below,
P(X≤1700)=1−e−1/1400×1700
=1−e−1.21=0.703
The resultant probability is 0.703
Let Y be a lifetime of another lamp two bulbs
Then the Z = X + Y will follow gamma distribution that is,
X+Y=Z∼gamma(2,1/1400)
2λZ∼
X+Y=Z∼gamma(2,1/1400)
2λZ∼χ2α2
The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,
P(Z≤1700)=P(1/700Z≤1.67)=
P(χ24≤1.67)=0.3614
The resultant probability is 0.3614
Hi!
You can think of this question like the photos attached above.
Hope this helps! Best of luck!
