Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
w=-11/6
Step-by-step explanation:
Answer:
sure
Step-by-step explanation:
Answer:
5 11/85
Step-by-step explanation:
First see how many times a whole number can be found.
436/85 = 5.1294
The denominator goes into the numerator 5 times.
Now we find a new numerator.
436 - (85 * 5) = 11 (this is the amount left over after we made 5 wholes.)
Now we see 5 11/85
It cannot be simplified further.
