Question

Sqrt2y-5+8=4 what Is the root

Answer 1

Answer:

The root of $\sqrt{2y-5} +8 = 4$ is 10.5.

Step-by-step explanation:

Given that,

$\sqrt{2y-5} +8 = 4$

As we have a square root term along with a single term on left side. We will move the single term on right side.

$\sqrt{2y-5} = 4-8$

$\sqrt{2y-5} = -4$

Taking the square on both sides, we get

$(\sqrt{2y-5})^2 = (-4)^2$

Square will cancel the impact of square root, therefore:

$({2y-5}) = 16$

$2y = 16+5$

$2y = 21$

$y = \frac{21}{2}$

$y = 10.5$

Therefore, the root of $\sqrt{2y-5} +8 = 4$ is 10.5.