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rusak2 [61]
3 years ago
13

Erica has already knit 5 centimeters of scarf, and can knit 1 centimeter each night. Write an equation that shows the relationsh

ip between the nights x and the length knit y
Mathematics
1 answer:
ollegr [7]3 years ago
4 0

Answer:

5+x=y

Step-by-step explanation:

If she has already knit 5 cm you will always have to factor that in. If x is the number of nights adding the number of nights she does 1 cm of knitting will give you the length she has knit so far (y). I hope this helped! Good luck

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James drove 986 miles from Philadelphia to Orlando in 14.5 hours. He continued to drive at the same average speed and drove anot
VMariaS [17]

Answer:

James Spent 25 hours driving from  Philadelphia to New Orleans.

Step-by-step explanation:

Given:

Distance from Philadelphia to Orlando = 986 miles

Time required to travel Philadelphia to Orlando = 14.5 hrs

Distance from Orlando to New Orleans = 714 mile.

We need to find the total amount of time James spent driving from Philadelphia to New Orleans.

Solution:

First we will find the average speed from Philadelphia to Orlando.

We know that;

Speed is equal to distance divided by time.

framing in equation form we get;

average speed from Philadelphia to Orlando = \frac{986}{14.5}=68\ mi/hrs

Now given that he traveled with same speed from Orlando to New Orleans.

So we will find the time required from Orlando to New Orleans.

We know that;

Time is equal to Distance divided by speed.

framing in equation form we get;

time required from Orlando to New Orleans = \frac{714}{68}= 10.5 \ hrs

Now we will find the total time James spent on driving from Philadelphia to New Orleans.

the total time James spent on driving from Philadelphia to New Orleans is equal to sum of Time required to travel Philadelphia to Orlando and time required from Orlando to New Orleans.

framing in equation form we get;

the total time James spent on driving from Philadelphia to New Orleans = 14.5 + 10.5 = 25 hours.

Hence James Spent 25 hours driving from  Philadelphia to New Orleans.

6 0
3 years ago
A scuba diver wants to descend at an average rate of at least 7 feet per minute for 5 minutes. The table shows how many feet the
gladu [14]

The scuba diver must descend 3 feet in the fifth minute to meet the goal.

Why?

To find how many feet does the scuba diver need to descend to reach the goal of 35 feet in 5 minutes, we need to calculate how many feet he did descend on the first 4 minutes.

So, calculating we have:

FirstMinute=9ft\\SecondMinute=11ft\\ThirdMinute=5ft\\FourthMinute=7ft\\Total=9ft+11ft+5ft+7ft=32ft\\\\Goal=35ft\\\\Needed=Goal-Total(4Minutes)\\\\Needed=35ft-32ft=3ft

Hence, we can see that at the 4 minute, he has only descended 32ft. It means that he need to descend 3 feet more in the fifth minute.

Have a nice day!

7 0
3 years ago
Write an equation in point-slope form for the line that has the given slope m
meriva

Answers:

13) y + 2 = 1/4x

14) y - 1 = -2x

7 0
3 years ago
In the graph below, Point A represents Owen's house, Point B represents David's house and Point C represents the school. Who liv
ycow [4]

Answer:

• David

,

• 4 miles

Explanation:

In the graph:

The given locations are:

• Owen's House, A(11,3)

,

• David's House, B(15,13)

,

• School, C(3,18)

We determine both Owen's and David's distance from the school using the distance formula.

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Owen's distance from school (AC)

\begin{gathered} AC=\sqrt[]{(3-11)^2+(18-3)^2} \\ =\sqrt[]{(-8)^2+(15)^2} \\ =\sqrt[]{64+225} \\ =\sqrt[]{289} \\ AC=17\text{ miles} \end{gathered}

David's distance from school (BC)

\begin{gathered} BC=\sqrt[]{(3-15)^2+(18-13)^2} \\ =\sqrt[]{(-12)^2+(5)^2} \\ =\sqrt[]{144+25} \\ =\sqrt[]{169} \\ BC=13\text{ miles} \end{gathered}

We see from the calculations that David lives closer to the school, and by 4 miles.

The graph below is attached for further understanding:

5 0
1 year ago
HELP I HAVE ONLY 1 MIN TO ANSWER IT HELP(((((((&&&&
LenKa [72]

Answer:

the one you have marker is correct

Step-by-step explanation:

5 0
3 years ago
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