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3 years ago

Graph on a number line. −67

Mathematics

2 answers:

miskamm [114]3 years ago

8 0

Answer:

Here you go

Step-by-step explanation:

i just drew it/. you werent specific so this is it

r-ruslan [8.4K]3 years ago

8 0

Answer:

Here you go! I graphed it.

Step-by-step explanation:

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Why is it useful to factor polynomial expressions for a given scenario?

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To determine the roots or the zeros of the polynomial. These are the x-intercepts.

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3 years ago

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4 years ago

1 — 3 (9x + 3) = 3x + 1

Hatshy [7]

Answer: x = -0.3

Step-by-step explanation:

Given expression

1 - 3 (9x + 3) = 3x + 1

Expand parentheses and apply the distributive property

1 - 27x - 9 = 3x + 1

Combine like terms

(1 - 9) - 27x = 3x + 1

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-8 - 27x - 3x = 3x + 1 - 3x

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Add 8 on both sides

-8 - 30x + 8 = 1 + 8

-30x = 9

Divide - 30 on both sides

(-30)x / (-30) = 9 / (-30)

(-30)x / (-30) = 3 / (-10)

$\boxed{x=-0.3}$

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3 years ago

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If an initial amount A0 of money is invested at an interest rate i compounded times a year, the value of the investment after t

seropon [69]

Answer:

Following are the solution to the given point:

Step-by-step explanation:

Please find the comp[lete question in the attached file.

Given:

$\bold{ \lim_{n \to \ \infty} (1+ \frac{r}{n})^{nt} =e^{rt}}$

In point 1:

$\to y = (1+ \frac{r}{n})^{nt}$

In point 2:

$\to \ln (y)= nt \ln(1+ \frac{r}{n})$

In point 3:

Its key thing to understand, which would be that you consider the limit n to $\infty$ , in which r and t were constants!

$=lim_{n \to \ \infty} \ln (y) = lim_{n \to \ \infty} nt \ln(1+\frac{r}{n})\\\\= lim_{n \to \ \infty} \frac{\ln(1+\frac{r}{n})}{\frac{1}{nt}}\\\\= lim_{n \to \ \infty} \frac{\frac{-r}{\frac{n^2}{(1+\frac{r}{n})}}}{- \frac{1}{n^2t}}\\\\= lim_{n \to \ \infty} \frac{\frac{rn^2t}{n^2}}{(1+\frac{r}{n})}\\\\= lim_{n \to \ \infty} \frac{rt}{(1+\frac{r}{n})}\\\\= \frac{rt}{(1+\frac{r}{0})}\\\\=rt$