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Mademuasel [1]
3 years ago
10

Please answer quickly ASAP: How do you find the area of a trapezoid?

Mathematics
1 answer:
erica [24]3 years ago
5 0

Answer:

To find the area of a trapezoid, multiply the sum of the bases (the parallel sides) by the height (the perpendicular distance between the bases), and then divide by 2.

Step-by-step explanation:

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-4 times a number plus 29
kipiarov [429]
-4x+29? I think that's what you're asking.
8 0
3 years ago
A sold a commodity to b at 10% profit b again sold it to a at 10% loss. What does a have
ozzi
Let's answer this step-by-step.

First of all, let's estsblish the original price of the commodity as being 100%. Therefore:

Original price of commodity = 100%

Then, when A sold the commodity to B, it was sold at a 10% profit. Therefore:

Price of commidity when A sold to B:
100% x 1.1 = 110%

After that, when B sold it back to A, it was sold at a 10% loss. Therefore:

Price of commodity when B sold to A:
110% x 0.9 = 99%

Hence, A now has 99% of the original value of the commidity.
6 0
3 years ago
What are the coordinates of the point plotted on this graph?
laila [671]

The answer is C: (-1, -8)

4 0
3 years ago
Read 2 more answers
IM 20 MIN AWAY FROM FAILING PLZZZ HELPPPP​
padilas [110]

Answer:

13 and 32

Step-by-step explanation:

let one number be x

Then the other number is x + 19 , then

x + x + 19 = 45

2x + 19 = 45 ( subtract 19 from both sides )

2x = 26 ( divide both sides by 2 )

x = 13

The 2 numbers are 13 and 13 + 19 = 32

5 0
3 years ago
The midpoint of the coordinates (3, 15) and (20,8) is -
Nat2105 [25]

Answer:

The midpoint of the given coordinates is (\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5).

Step-by-step explanation:

We have given two coordinates (3,15) and (20,8).

Let we have given a line segment PQ whose P coordinate is (3,15) and Q coordinate is (20,8).

We have to find out the mid point M(x,y) of the line segment PQ.

Solution,

By the mid point formula of coordinates, which is;

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

On substituting the given values, we get;

M(x,y)=(\frac{3+20}{2}, \frac{15+8}{2})\\\\M(x,y)=(\frac{23}{2},\frac{23}{2})

We can also say that M(x,y)=(11.5,11.5)

Hence The midpoint of the given coordinates is (\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5).

3 0
3 years ago
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