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3 years ago

A student attempted to generate an equivalent expression using the distributive property, as shown below:

Mathematics

1 answer:

Stells [14]3 years ago

4 0

He didn't multiply the y by 7

$7(y-5) = 7y-35$

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Kim has a lawn service business. The equation 165 – 105x + 3y = 0 relates y, her weekly profits , and 2, the number of lawns she

Ede4ka [16]

Answer:

1. -105

2. 3

3. 165

1. -35

2. 55

3. y= mx + b

= -105 + 0

= -105

4 0

3 years ago

The following set is bimodal. PLZ ANSWER ASAP

polet [3.4K]

Im srry but in my calculations thinking this following statement might be true thats what i say so my answer is(true)
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8 0

3 years ago

Read 2 more answers

Allentown got 2 feet less than twice the amount of snow Georgetown got . Allentown got 3 feet more snow than Georgetown. How man

Mandarinka [93]

x=2y-2

x=y+3

Substitute the second equation into the first

y+3=2y-2

solve for y

y=5

plug into original

x=y+3=5+3=8 or x=2(5)-2=8

Allentown got 8 ft of snow, Georgetown got 5 ft of snow.

4 0

3 years ago

Read 2 more answers

Expand the given power using the Binomial Theorem. (10k – m)5

agasfer [191]

Answer:

$(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}$

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

$(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}$

∵ The binomial is $(10k-m)^{5}$

∴ a = 10k , b = -m and n = 5

∴ $(10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}$

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ $(10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})$

∴ $(10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}$

5 0

3 years ago

Johnathon can jog 3 2/5 miles in 7/8 hour. Find his average speed in miles per hour

Alex777 [14]

<span>We have to calculate the average speed if we know the distance and time that Johnatan can jog. The distanece: d = 3 2/5 miles = 3.4 miles. t = 7/8 hour = 0.875 h. Then we will use the formula for the average speed ( velocity ): v = d / t. v = 3.4 m / 0.875 h = 3.866 mph. Answer: The average speed is 3.866 mph.</span>

8 0

3 years ago