Answer:
A) firm offer rule
Explanation:
The firm offer rule states that an offer shall remain open and firm until its expiration date (in this case a fortnight). Stelwire LLC can revoke an offer (anyone can) but in order to do so, it must notify the other party about the revocation. If Stelwire LLC didn't properly revoke the offer before Ralph accepted it, then they are liable for it.
Answer:
Date Account title Debit Credit
12/31/2019 Lease Receivable $175,934
Cost of Goods sold $120,000
Sales Revenue $175,934
Inventory $120,000
Date Account title Debit Credit
12/31/2019 Cash $40,800
Deposit Liability $40,800
The rental amount is constant and is made on the first day of the lease period so this is an annuity due.
As the collectability is probable, you need to find the present value of this lease:
= 40,800 * Present value of annuity due factor, 5 year, 8%
= 40,800 * 4.3121
= $175,933.68
= $175,934
Answer:
Delwazic Inc. is a multinational corporation (MNC) that creates products specialized for a few host countries. It manufactures berets in France, cowboy hats in the United States, bowlers in the United Kingdom, and bush hats in Australia. In this scenario, Delwazic Inc. is most likely a monopolist
Explanation:
A monopolist is solely responsible for sales of products to many buyers, such market is termed a monopoly market
Answer:
$12.22 per share
Explanation:
The computation of the stock price one year from now is shown below;
Current EPS = Net Income ÷ Number of shares
= $95,000,000/5,500,000
= $17.2727
Now
P/E Ratio = Market Price per share ÷ Earnings per share
= $14.75 ÷ 17.2727
= 0.8539 times
Now
Revised EPS = $95,000,000 × 1.25 ÷ 8,300,000
= $14.3072
So, the Price is
= 14.3072 × 0.8539
= $12.22 per share
<span>25 years: No Payment, but total is 250000
6 months earlier. Payment of "P". It's value 1/2 year later is P(1+0.03)
6 months earlier. Payment of "P". It's value 1 year later is P(1+0.03)^2
6 months earlier. Payment of "P". It's value 1½ years later is P(1+0.03)^3
6 months earlier. Payment of "P". It's value 2 years later is P(1+0.03)^4
</span><span>We need to recognize these patterns. Similarly, we can identify the accumulated value of all 50 payments of "P". Starting from the last payment normally is most clear.
</span>
<span>P(1.03) + P(1.03)^2 + P(1.03)^3 + ... + P(1.03)^50
That needs to make sense. After that, it's an algebra problem.
P[(1.03) + (1.03)^2 + (1.03)^3 + ... + (1.03)^50]
</span>
P(<span><span>1.03−<span>1.03^51)/(</span></span><span>1−1.03) </span></span>= <span>250000</span>