Answer:
x = ± 3, x = ± 2i
Step-by-step explanation:
Given
f(x) = (x² + 4)(x² - 9)
To find the zeros let f(x) = 0, that is
(x² + 4)(x² - 9) = 0
Equate each factor to zero and solve for x
x² - 9 = 0 ( add 9 to both sides )
x² = 9 ( take the square root of both sides )
x = ± = ± 3
x² + 4 = 0 ( subtract 4 from both sides )
x² = - 4 ( take the square root of both sides )
x = ± = ± = ± × = ± 2i
Thus zeros are
x = - 3, x = 3 ← real
x = - 2i, x = 2i ← complex
Answer:
Considering the fact that A, B, and C are correct I can say that D is definitely your answer
Answer:
x = 2
y = 1
Step-by-step explanation:
-2x-3y=-7, y=6x-11
-2x - 3(6x - 11) = -7
-2x - 18x + 33 = -7
-2x - 18x = -40
-20x = -40
<u><em>x = 2</em></u>
y = 6(2) - 11
y = 12 - 11
<u><em>y = 1</em></u>