All categories

3 years ago

-3-4(4x-8)=3(-8x-1) I will give BRAINLIEST! show all steps please :(

Mathematics

2 answers:

Aleks [24]3 years ago

7 0

Answer:

x = -4

Step-by-step explanation:

Recall the Order of Operations rules:

Any work enclosed in parentheses must be done first if possible; in this particular problem, nothing inside parentheses is possible.

Next: multiplication and division, and

Finally: addition and subtraction.

Thus, we must focus on the multiplication -3(4x - 8) and 3(-8x - 1) first:

-3 -16x + 32 = -24x - 3

Adding 3 to both sides simplifies this equation to -16x + 32 = -24x.

Adding 16x to both sides isolates x on the right side: 32 = -8x.

Finally, x = -32/8, or x = -4

mixer [17]3 years ago

3 0

Step-by-step explanation:

-3-4 -32x=3×8x

-3-4-32x=24x

-6=32x+24x

-6=56x

:. x=-28/3

You might be interested in

Helpppp pleaseeee !!!!!

Elan Coil [88]

Answer:

should be 4 square units

the base of the triangle is 1 and the height is 8 so you do 1x8 the divide by 2 to get 4 so then you get the area.

7 0

3 years ago

Read 2 more answers

Simplify. Assume that no denominator is equal to zero. (show work) help please!!!!!

MrRa [10]

n^8

basically it's like this n^12/n^4 = n^(12-4) = n^8

5 0

3 years ago

Another name for Spherical Geometry is

Minchanka [31]

Another name for Spherical Geometry is (a.) Euclidean. A sphere is not an Euclidean essentially, but the laws of this geometry are close estimations.

3 0

3 years ago

A recipe used 2/3 cup of sugar for every 2 teaspoons of butter. How much sugar was used per teaspoon of butter

myrzilka [38]

Answer:

2/3cups 2 teaspoons

(2/3 )cups/2teaspoons =1/3 cups per teaspoon

Answer= 1/3 cups per teaspoon

8 0

3 years ago

Read 2 more answers

Evaluate the definite integral. 1 x4(1 + 2x5)5 dx.

Nata [24]

Answer:

Step-by-step explanation:

Given the definite integral $\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx$ , we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

$= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}$

$= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} } \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du } \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}] \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\$

$= \dfrac{u^{-4}}{40} \\\\\\= \dfrac{1}{40u^4} +C$

substitute u = 1-2x⁵ into the result

$= \dfrac{1}{40(1-2x^5)^4} +C$

Hence $\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx$ $= \dfrac{1}{40(1-2x^5)^4} +C$

5 0

3 years ago