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2 years ago

15

Which figure represents the image of parallelogram

1 answer:

NeTakaya2 years ago

7 0

Answer: The answer would most likely be Figure A

Step-by-step explanation:

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Match each description when z = 9 + 3i. 1. Real part of z 2. Imaginary part of z 3. Complex conjugate of z 4. 3i - z 5. z - 9 6.

sergey [27]

$1)\quad \Re(9+3i)=9\qquad\text{F}\\\\
2)\quad \Im(9+3i)=3\qquad\text{E}\\\\
3)\quad \overline{(9+3i)}=9-3i\qquad\text{D}\\\\
4)\quad 3i-(9+3i)=3i-9-3i=-9\qquad\text{A}\\\\
5)\quad 9+3i-9=3i\qquad\text{B}\\\\
6)\quad 9-(9+3i)=9-9-3i=-3i\qquad\text{C}\\\\$

5 0

3 years ago

Help please<br><br><br> asap<br><br><br> thanks

sleet_krkn [62]

It would be B

Hope this helps! ;)

4 0

3 years ago

What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

3 years ago

Sidney wants to buy a charm bracelet.

attashe74 [19]

Answer:

whats the question

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Simplify by combining like terms: 15x +2 - 7 - 5x

Step2247 [10]

Answer:

10x-5

Step-by-step explanation:

You subtract 15x-5=10x. Then you do -7+2. The 7 is negative . So it would be -7 plus two. So it would equal -5. So it's 10x-5

5 0

2 years ago