Answer:
6500 cm^3.
Step-by-step explanation:
That would be the volume of the large box - the volume of the cube
= 15*25*20 - 10^3
= 7500 - 1000
= 6500 cm^3.
Let's solve for x.
5x+15y=12
Step 1: Add -15y to both sides.
5x+15y+−15y=12+−15y
5x=−15y+12
Step 2: Divide both sides by 5.
5x
5
=
−15y+12
5
x=−3y+
12
5
Answer:
x=−3y+12/5
Let's solve for y.
5x+15y=12
Step 1: Add -5x to both sides.
5x+15y+−5x=12+−5x
15y=−5x+12
Step 2: Divide both sides by 15.
15y
15
=
−5x+12
15
y=
−1
3
x+
4
5
Answer:
y=-1/3x+4/5
Hope this helps!
-Josh
brainliest?
Answer:
1.28/7. 2.-17/7. 3.-11/-3. 4.not sure. 5. cant remeber rest
Solving the given inequality for d, we get...
6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83
Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}
The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6
Given 2.50x + 3.50y < 30.
Where x represent the number of hamburgers and y represent the number of cheeseburgers.
Now question is to find the maximum value of hamburgers Ben could have sold when he has sold 4 cheeseburgers.
So, first step is to plug in y=4 in the given inequality. So,
2.50x+3.50(4)<30
2.50x+14 <30
2.50x<30- 14 Subtracting 14 from each sides.
2.50x< 16
Dividing each sides by 2.50.
x<6.4
Now x being number of hamburgers must be an integer , so tha maximum value of x can be 6,
thus x = 6 hamburgers
So, the maximum value of hamburgers Ben could have sold is 6*2.5=$15
Hope this helps!!
