Answer:
I think it would be around $1.33 for each kg
Step-by-step explanation:
You would divide 12 by 9. Once you do that, you get 1.33
What is the mode of this data set? {8, 11, 20, 10, 2, 17, 15, 5, 16, 15, 25, 6}
lidiya [134]
The mode is what appears the most so 15 is the answer because it appears the most.
Answer:
AB/DE=BC/EF=AC/DF
Step-by-step explanation:
Corresponding segments are designated by letters in corresponding positions in the triangle names. For example, of one segment is designated using the 1st and 2nd letters of one triangle name (such as AB), then the corresponding segment is designated using the 1st and 2nd letters of the other triangle name (such as DE).
Corresponding segments are proportional in length. Corresponding angles are congruent.
We know that
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another.
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.
</span>we have that
<span>Circle 1 is centered at (4,3) and has a radius of 5 centimeters
</span><span> Circle 2 is centered at (6,-2) and has a radius of 15 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
</span>the transformation has the following rule
(x,y)--------> (x+2,y-5)
so
(4,3)------> (4+2,3-5)-----> (6,-2)
so
center circle 1 is now equal to center circle 2
<span>The circles are now concentric (they have the same center)
</span>
step 2
A dilation is needed to increase the size of circle 1<span> to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 15/5----> 3
radius circle 1 will be=5*scale factor-----> 5*3-----> 15 cm
radius circle 1 is now equal to radius circle 2
A translation, followed by a dilation<span> will map one circle onto the other, thus proving that the circles are similar</span>
Answer:
A. 
and 
Step-by-step explanation:
Given:
Vertices of triangle RST are 
and 
.
Rotation is 90° about the center O(0,0). The rotation is counter-clockwise as the angle of rotation is positive.
Now, the co-ordinate rule for 90° rotation counter-clockwise is given as:
→ 
and 
values interchange their places with becoming negative when interchanged.
So, 
→ 
→ 
→ 
⇒ → 
Therefore, the image of the vertices are and .
