Step-by-step explanation:
A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :
f(t) = -32 t+285
Height of the ball is :
C is constant. Here the ball is launched from a height of 6 feet. So,
At t = 2 s, 
At t = 9 s, 
Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.
Slope = (y2 - y1) / (x2 - x1)
(-9,6)....x1 = -9 and y1 = 6
(-3,9)...x2 = -3 and y2 = 9
now we sub and solve
slope = (9 - 6) / (-3 - (-9) = 3 / (-3 + 9) = 3/6 = 1/2 <=
The circle with center (h, k) and radius r has equation
.. (x -h)^2 +(y -k)^2 = r^2
You have
.. h = 2
.. k = 0
.. r = √5
The center is (h, k) = (2, 0).
What the triangle format? what does it look like? it all depends.
