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fredd [130]
3 years ago
8

Brian and Carlos are sharing a large sub sandwich. Brian ate 2 / 5 of the sandwich, and Carlos ate 1 / 5 of the sandwich. How mu

ch of the sandwich is left over?
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
8 0

if I'm right it would be 2/5. you get your answer by adding 2/5 and 1/5 then subtract 5/5- 3/5 to get 2/5

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A 180 ft long board is cut into 3 pieces. The second piece of
blagie [28]

Answer:

20 feet

Step-by-step explanation:

1st piece = x

2nd piece = 2x

3rd piece = 6x

x+2x+6x=180

9x=180

x=20

so the first piece is 20 feet, the second is 40, and the third is 120.

6 0
3 years ago
Read 2 more answers
Please help me
Hatshy [7]

Answer:

$2 for 1 rose bush and $2 for one shrub

Step-by-step explanation:

32=2x+14y

26=11x+2y

32=2(2)+14(2)

32=4+28

32=32

26=11(2)+2(2)

26=22+4

26=26

Since both equations come out correct the cost of 1 rose bush is 2 dollars and the cost of one shrub is 2 dollars. kinda cool

6 0
3 years ago
Read 2 more answers
Please answer with clear instructions so that i can apply this to other questions
marishachu [46]

Answer:

1 and - 1

Step-by-step explanation:

The equation of a line passing through the origin is

y = mx ( m is the slope ( gradient ) )

y = x ← is in this form

with gradient m = 1

Parallel lines have equal gradients

Then the gradients of lines parallel to the given line is 1

Given a line with gradient m then the gradient of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{1} = - 1

Then the gradients of lines perpendicular to this line is - 1

4 0
2 years ago
A building across the street casts a shadow that is
tensa zangetsu [6.8K]

Answer:

The building is 36 feet tall.

Step-by-step explanation:

Divide 6 by 4 then multiply by 24.

3 0
3 years ago
What is an equation for a sine curve with amplitude 2, and period 4pi radians ?
Nezavi [6.7K]
<span>1. a sine curve with amplitude 2, and period 4pi radians
</span>
the general equation of the sine curve ⇒⇒ y = a sin (nθ)
where: a is the amplitude  and  n = 2π/perid
∵ <span>amplitude 2, and period 4pi radians
</span>
∴ y = 2 sin (θ/2)

The correct answer is option D. y = 2 sin (θ/2)
===========================================

<span>2.The period and amplitude of the function ⇒⇒ y = 5 cos 2θ
</span>
<span>comparing with y = a cos nθ
</span>
where : a is the amplitude  and  n = 2π/period
<span>amplitude = 5  , period = 2π/n = 2π/2 = π
</span>

The correct answer is option B. Period: pi radians: Amplitude:5

============================================================
3. tan (2π/3) = tan 120° = -√3 
120° lie in the second quadrant and its reference angle = 180° - 120° = 60°
tan function in the second quadrant is negative
∴ tan 120° = - tan 60 = -√3

The correct answer is C. -sqrt3

=====================================================
4. <span>Tan 5π/6 = tan 150° = -(√3)/3
</span>
150° lies in the second quadrant and its reference angle = 180° - 150° = 30°
tan function in the second quadrant is negative
∴ tan 150° = - tan 30 = -(√3)/3

The correct answer is <span>B.-sqrt3/3</span>
8 0
3 years ago
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