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snow_lady [41]
3 years ago
12

Please help and explain please

Mathematics
1 answer:
butalik [34]3 years ago
4 0
The greatest remainder with 3 is 2, the greatest remainder with 8 is 7, and the greatest remainder with 5 is 4, all because if it was one more then it would not be remaining and it would be without a remainder. Hope this helps!
You might be interested in
Simplify the expression
Ronch [10]

Answer:

(3 x)/(5 x + 2)

Step-by-step explanation:

Simplify the following:

(3 x^2)/(5 x^2 + 2 x)

Hint: | Factor common terms out of 5 x^2 + 2 x.

Factor x out of 5 x^2 + 2 x:

(3 x^2)/(x (5 x + 2))

Hint: | For all exponents, a^n a^m = a^(n + m). Apply this to (3 x^2)/(x (5 x + 2)).

Combine powers. (3 x^2)/(x (5 x + 2)) = (3 x^(2 - 1))/(5 x + 2):

(3 x^(2 - 1))/(5 x + 2)

Hint: | Evaluate 2 - 1.

2 - 1 = 1:

Answer:  (3 x)/(5 x + 2)

8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=what%20%5C%3A%20is%20%5C%3A%204%20%5Cdiv%206%20-%2010%20%20%5C%5C%20" id="TexFormula1" title="
amm1812
The answer is -28/3 or 9.33333333333 have a great day also could I get brainliest
6 0
3 years ago
SOLVE FOR BRAINLIST!!
Natasha_Volkova [10]
The correct answer is c
6 0
3 years ago
A physician orders 140mg of a medication to give orally. You have 125mg/5mL on hand. What is the correct dose of medication to g
adelina 88 [10]
<h2>Hello!</h2>

The answer is: The correct dose of medication to give is 5.6 mL

<h2>Why?</h2>

To solve this problem we need to establish a relationship between the prescripted medication and the available solution.

Let's write the needed equations to establish the relantionship:

\frac{125mg}{5mL}=1\\\\125mg=5mL

The available solution means 125 mg each 5 mL of solution, so:

\frac{125mg}{5mL}=\frac{140mg}{x}\\\\x*\frac{125mg}{5mL}=140mg\\\\x=140mg*\frac{5ml}{125mg}=\frac{700mg*mL}{125mg}=5.6mL

Hence, the correct dose of medication to give is 5.6 mL of the 125 mg/5mL solution.

Have a nice day!

3 0
3 years ago
Plz help I need answer asap
Dimas [21]
Gchdbncxthysshj teethed how
4 0
2 years ago
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