Question

Consider △LMN. m∠L + m∠M = ° sin(L) = sin(M) = I got y’all

Answer 1

Answer:

90°

cos(M)

cos(L)

Step-by-step explanation:

In a triangle the sum of the three angles is 180°. Here the triangle is a right angled triangle so,

∠L+∠M = 90

which can be seen by adding the angles

42°+48° = 90°

$sin(L)=\frac{\text{Opposite side}}{\text{hypotenuse}}\\\Rightarrow sin (L)=\frac{MN}{ML}$

$cos(M)=\frac{\text{Adjacent side}}{\text{hypotenuse}}\\\Rightarrow cos(M)=\frac{MN}{ML}$

∴$\mathbf{sin(L)=cos(M)=\frac{MN}{ML}}$

$sin(M)=\frac{\text{Opposite side}}{\text{hypotenuse}}\\\Rightarrow sin (M)=\frac{LN}{ML}$

$cos(L)=\frac{\text{Adjacent side}}{\text{hypotenuse}}\\\Rightarrow cos(L)=\frac{LN}{ML}$

∴$\mathbf{sin(M)=cos(L)=\frac{LN}{ML}}$

Answer 2

m∠L + m∠M = 90°

sin(L) =  cos(M)

sin(M) = cos(L)

lol nice