All categories

4 years ago

Angles C and E are supplementary. The M>C = 112 and M>E = (3x + 50) Solve for X.

Mathematics

1 answer:

jolli1 [7]4 years ago

4 0

Answer:

Step-by-step explanation:

If angles C and E are supplementary then they add up to be 180 degrees.

So we have:

$112+(3x+50)=180$

$112+3x+50=180$

Using commutative property to gather like terms:

$3x+112+50=180$

Simplify:

$3x+162=180$

Subtract 162 on both sides:

$3x=180-162$

Simplify:

$3x=18$

Divide both sides by 3:

$x=\frac{18}{3}$

$x=6$

Check:

If $x=6$ then the measurement of angle E is $(3 \cdot 6+50)=68$ .

The measurement of angle C plus the measurement of angle E is:

112+68=180.

You might be interested in

What is 10*9*8*7*6*5*4*3*2*1?

nordsb [41]

Welcome to the factorial world :) Remember the Exclamation Point ( ! ) on the calculator, that is called factorial.
For instance: 1! = 1
2! = 1 x 2
3! = 1 x 2 x 3
and so on
10! = 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10 = 3628800
Crazy enough, 0! is actually equal to 1, try that on your calculator XD

6 0

3 years ago

Which statement comparing 6² + 14 ÷ 2 and 100−82 is true?

DanielleElmas [232]

6*6 =36
14/2 =7
36+7= 43

100-82= 18

43 > 18

therefore A is truw

5 0

3 years ago

Read 2 more answers

Marcus earned $230 for 40 hours of work. Phillip earned $192 for 32 hours of work. Are these pay rates proportional? Explain.

Zigmanuir [339]

Answer:

No.

Step-by-step explanation:

Find ROC for Marcus and Phillip

Marcus

230/40 = $5.75 per hour

Phillip

192/32 = $6 per hour

$6 > $5.75

8 0

3 years ago

Read 2 more answers

The table shows the relationship between time spent running and distance traveled in which type of model best describes the rela

crimeas [40]

Answer:

Relationship is linear as r is closest to 1.

Step-by-step explanation:

From statistics we know that,

$\text{Corelation Coefficient}=r=\dfrac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2-(\sum x)^2][n\sum y^2-(\sum y)^2]]}}$

Putting all the values from the table,

we get corelation factor as 0.9995

Therefore, the relationship is linear as r is closest to 1.

8 0

3 years ago

Read 2 more answers

Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then

olchik [2.2K]

Answer:

It is proved that $\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Step-by-step explanation:

Given vector field,

$F=P\uvec{i}+Q\uvec{j}+R\uvec{k}$

Where,

$P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}$

To show,

$\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Consider,

$\frac{\partial P}{\partial y}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial y\partial x}=\frac{\partial^2 f}{\partial x\partial y}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial y})=\frac{\partial Q}{\partial x}$

$\frac{\partial P}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial z\partial x}=\frac{\partial^2 f}{\partial x\partial z}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial x}$

$\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}$

Hence proved.

4 0

3 years ago