Answer:
The answer is below
Step-by-step explanation:
Let S denote syntax errors and L denote logic errors.
Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56
a) The probability a program contains both error types = P(S ∩ L)
The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L) - P(L) = 56% - 47% = 9%
The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%
b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
c) The probability a program has logic errors, but not syntax errors = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
Answer:
D,4 times as large as the expressian
Step-by-step explanation:
because 4x is multiplucation so it means that it multiplys that number
Answer:
Step-by-step explanation:
We need to find out the LCM of 56 , 42 , 28 . So Lowest Common Multiple known as LCM is the lowest multiple which is divisible by all the numbers whose LCM is taken out . It can we done by two methods. Both of which are discussed in the attachment .
For complete solution kindly refer to the attachment .
<u>Related</u><u> Information</u><u> </u><u>:</u><u>-</u><u> </u>
<u>•</u><u> </u><u>HCF </u><u>:</u><u>-</u>
- It stands for Highest Common Factor . It is the highest numbers which divides out completely the numbers without leaving remainder of the numbers whose HCF is we are finding out .
Well if you have three and add negative 3 it equals 0
Answer:
D
Step-by-step explanation:
Well, since t = time in air, we already know that it traveled 2 seconds.
H = height in meters, and H = 18
So, after 2 seconds the object is 18m in the air
So, option D
