Question

I NEED HELP SOOOO MUCH IM SOOO LOST I WILL GIVE A BRAINLIEST TO THE PERSON WHO INCLUDES ALL WORK, CORRECT ANSWER,AND EVERYTHING MAKES SENSE.
(Variables on both sides of an equation)
Solve: 5(a-1)-15=3(a+2)+4

Answer 1

We start by using the distributive property to expand the terms $5(a-1)$ and $3(a+2)$. When we do, we obtain $5a-5$ and $3a+6$.

Putting those back into our equation, we have:

$5a-5-15=3a+6+4$

Next, we combine all of the constants on either side:

$5a-20=3a+10$

Finally, we want to get the variable a by itself on one side of the equation, so we perform the following steps to isolate it:

$5a=3a+30$ (Add 20 to both sides)
$2a=30$ (Subtract 3a from both sides)
$a=30/2=15$ (Divide both sides by 2 to isolate a)

So, we obtain our answer of $a=15$.

Answer 2

5(a-1) - 15 = 3(a+2) + 4
Open all parenthesis and distribute
5a - 5 - 15 = 3a + 6 + 4
Simplify
5a - 20 = 3a + 10
Add both sides by 20 and subtract both sides by 3a
2a = 30
a = 15