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sweet [91]
3 years ago
7

I NEED HELP SOOOO MUCH IM SOOO LOST I WILL GIVE A BRAINLIEST TO THE PERSON WHO INCLUDES ALL WORK, CORRECT ANSWER,AND EVERYTHING

MAKES SENSE.
(Variables on both sides of an equation)
Solve: 5(a-1)-15=3(a+2)+4
Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
6 0
We start by using the distributive property to expand the terms 5(a-1) and 3(a+2). When we do, we obtain 5a-5 and 3a+6.

Putting those back into our equation, we have:

5a-5-15=3a+6+4

Next, we combine all of the constants on either side:

5a-20=3a+10

Finally, we want to get the variable a by itself on one side of the equation, so we perform the following steps to isolate it:

5a=3a+30 (Add 20 to both sides)
2a=30 (Subtract 3a from both sides)
a=30/2=15 (Divide both sides by 2 to isolate a)

So, we obtain our answer of a=15.
alexandr402 [8]3 years ago
5 0
5(a-1) - 15 = 3(a+2) + 4
Open all parenthesis and distribute
5a - 5 - 15 = 3a + 6 + 4
Simplify
5a - 20 = 3a + 10
Add both sides by 20 and subtract both sides by 3a
2a = 30
a = 15
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