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Grace [21]
3 years ago
6

What is the missing reason in steps 7 and 8 of the proof?

Mathematics
2 answers:
PolarNik [594]3 years ago
8 0

Answer:

Step-by-step explanation:

The answer is option B) def of sine in right triangle

il63 [147K]3 years ago
4 0

Answer:Refer to the image attached.

Given:  and  are congruent.

To Prove: ABC is an isosceles triangle.

Construction: Construct a perpendicular bisector from point B to Line segment AC.

Consider triangle BAD and BCD,

(given)

(By the definition of a perpendicular bisector)

(By the definition of a perpendicular bisector)

Therefore,  by Angle Side Angle(ASA) Postulate.

Line segment AB is congruent to Line segment BC because corresponding parts of congruent triangles are congruent.(CPCTC)

Step-by-step explanation:

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Find the distance between the points given. (0,6) and (5,12)
Elan Coil [88]
d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}} \\d = \sqrt{(5 - 0)^{2} + (12 - 6)^{2}} \\d = \sqrt{(5)^{2} + (6)^{2}} \\d = \sqrt{25 + 36} \\d = \sqrt{61} \\d = 7.8 \\\\(x - h)^{2} + (y - k)^{2} = r^{2} \\(x - 5)^{2} + (y - 6)^{2} = 7.8^{2} \\(x - 5)^{2} + (y - 6)^{2} = 61 \\(h, k) = (5, 6)
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3 years ago
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I need help guys Find (f+g)(x)
mihalych1998 [28]
The answer would be D, I'm sure that is correct so you dont need to check <3 b e l i e v e i n m e
7 0
3 years ago
e) Given the following: Let X = {1, 2, 3, 4) and a relation R on X as R= {(1,2), (2,3), (3,4)}. Find the reflexive and transitiv
Naddika [18.5K]

Answer:

The answer is \{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}

Step-by-step explanation:

Remember that a reflexive relation R\subset \mathcal{P}(X), where \mathcal{P}(X) is the power set of X, is one which conteins the ordered pairs of the form (a,a), for a\in X.

So, As the reflexive and transitive closure of R (that we will denote by \overline{R}) is in particular reflexive, we must add to R  the elements \{(1,1) , (2,2),(3,3),(4,4) \}

A transitive relation R is one in which if the pair (a,b) and the pair (b,c) are in there, then the pair (a,c) must be there too.

So, to complete the relation R to be reflexive and transitive we must add the pair (1,3) (because (1,2),(2,3) are in R), the pair (2,4), and the pair (1,4) because we added the pair (2,4).

Therfore we have that \overline{R}=\{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}.

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3 years ago
HELP ME SOLVE HURRY I WILL MARK BRAINLIEST THANKS
adelina 88 [10]

Answer:

your y intercept is 90 and the equation would be y= 90 and x is unknown

5 0
2 years ago
Given the two half-reactions, what must be done in the next step before the reaction can be balanced? First: upper A u superscri
kenny6666 [7]

In the first reaction, Gold (Au) gets 3 electrons and became Gold. In the second reaction, Iodine (I) loses 2 electrons and became Iodine.

<h3>What are cations and anions?</h3>

When the atom loses the election then it is called a cation and when it gains the electron is called an anion.

Two reactions are given.

First reaction;

Au³⁺ + 3e⁻ ⇒ Au

In the first reaction, Gold (Au) gets 3 electrons and became Gold.

Second reaction;

2I⁻ ⇒ I₂ + 2e⁻

In the second reaction, Iodine (I) loses 2 electrons and became Iodine.

More about the cation and the anion link is given below.

brainly.com/question/1659592

8 0
2 years ago
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