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3 years ago

Takes a word processor 20 minutes to spell check 6 pages, how long to check 27 pages

Mathematics

1 answer:

ivann1987 [24]3 years ago

6 0

9514 1404 393

Answer:

90 minutes

Step-by-step explanation:

Assuming the time is proportional to the number of pages, you have ...

time/pages = 20/6 = T/27

Multiplying by 27 gives ...

T = 27(20/6) = 90

It is expected to take 90 minutes to check 27 pages.

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hich of these is a question you might ask before reading the selection titled, “Credit Cards-Credit Where Credit’s Due”? a. Do I

ch4aika [34]

Answer:

what do you mean what do you need me to work out

Step-by-step explanation:

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3 years ago

Nezzie is shopping for items for her daycare because the store is having a sale where everything in the store is 10% off. Nezzie

Harman [31]

Soo 100.26-15% off = $85.25 and 59.99 you need to crank it up 1 so $60-10% off=$54 last add $85.25+$54=$129.25

So no she is not right

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3 years ago

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What values of k will make the line containing points (k,3) and (-2,1) parallel to the line through (5, K) and (1,0)

rjkz [21]

Answer:

k = -4 or 2

Step-by-step explanation:

For the lines to be parallel, the lines would need to be the same slope. This means to find the slope of each we would take the difference of the rise over the run.

$\frac{1-3}{-2-k}=\frac{-2}{-2-k}$

and

$\frac{0-k}{1-5}=\frac{-k}{-4}$

To find K, set them equal.

$\frac{-2}{-2-k} = \frac{-k}{-4}\\-k(-2-k) = -2*-4\\2k+k^2=8\\k^2+2k-8=0$

Factor the quadratic and solve for K.

$(k+4)(k-2)=0$

k+4=0 so k=-4

k-2=0 so k=2

4 0

3 years ago

If a vertical line is dropped from the x-axis to the point (12, –9) in the diagram below, what is the value of sec?

dem82 [27]

Answer:

Value of $\sec \theta = \frac{5}{4}$

Step-by-step explanation:

Given: A vertical line is dropped from the x-axis to the point (12, -9) as shown in the diagram below;

To find the value of $\sec \theta$ .

By definition of secants;

$\sec \theta = \frac{1}{\cos \theta}$

Now, first find the cosine of angle $\theta$

As the point (12 , -9) lies in the IV quadrant , where $\cos \theta > 0$

Consider a right angle triangle;

here, Adjacent side = 12 units and Opposite side = -9 units

Using Pythagoras theorem;

$(Hypotenuse side)^2= (12)^2 + (-9)^2 = 144 + 81 = 225$

$Hypotenuse = \sqrt{225} =15 units$

Cosine ratio is defined as in a right angle triangle, the ratio of adjacent side to hypotenuse side.

$\cos \theta = \frac{Adjacent side}{Hypotenuse side}$

then;

$\cos \theta = \frac{12}{15} = \frac{4}{5}$

and

$\sec \theta = \frac{1}{\cos \theta}= \frac{1}{\frac{4}{5}} = \frac{5}{4}$

therefore, the value of $\sec \theta$ is, $\frac{5}{4}$

5 0

3 years ago

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Which of the following illustrates a phase shift?

Natasha_Volkova [10]

Answer:

A. y = -2 - cos(x-π)

Explanation:

The general form of the trig equation is:

y = A sin (Bx + C) + D

where:

A is the amplitude

$\frac{2\pi}{B}$ is the period

$\frac{-C}{B}$ is the phase shift

D is the vertical shift

Now, let's check the choices:

A. y = -2 - cos(x-π)

$\frac{-C}{B} = \frac{\pi}{1} = \pi$

Therefore, the function has a phase shift of π

B. y = 3 cos(4x)

$\frac{-C}{B} = \frac{0}{4} = 0$

Therefore, the function has no phase shift

C. y = tan(2x)

$\frac{-C}{B} = \frac{0}{2} = 0$

Therefore, the function has no phase shift

D. y = 1 + sin(x)

$\frac{-C}{B} = \frac{0}{1} = 0$

Therefore, the function has no phase shift

Based on the above, the correct answer is A

Hope this helps :)

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3 years ago

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