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mr Goodwill [35]
3 years ago
5

What are the real zeros of x^3 + 4x^2 − 9x − 36

Mathematics
1 answer:
ivanzaharov [21]3 years ago
6 0
X3 + 4x2 -9x -36 
[x3 + 4x2] -9 [ x+4] 
take x2 common factor from first praket
x2[x+4] -9 [x+4] 
= [x+4] *[x2 -9] 
so the zeros of this equation are -4 , 3, -3
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