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3 years ago

What are the real zeros of x^3 + 4x^2 − 9x − 36

1 answer:

6 0

X3 + 4x2 -9x -36
[x3 + 4x2] -9 [ x+4]
take x2 common factor from first praket
x2[x+4] -9 [x+4]
= [x+4] *[x2 -9]
so the zeros of this equation are -4 , 3, -3

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3 years ago

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2 years ago

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3 years ago

It is a six-digit whole number.

pogonyaev

Answer:

212121.

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2 years ago

2. Is 4x – 3 = 19 true, false, or open? <br> A)true<br> B)false<br> C)open

ElenaW [278]

Answer: B. False

Step-by-step explanation: Because you do

4x - 3 = 19

+3 +3 =4x = 22

You divide 4x divide by 4 and you get x

Then you divide 22 by 4 and get 5.5

So the answer is X = 5.5

6 0

3 years ago