Question

What are the real zeros of x^3 + 4x^2 − 9x − 36

Answer 1

X3 + 4x2 -9x -36 
[x3 + 4x2] -9 [ x+4] 
take x2 common factor from first praket
x2[x+4] -9 [x+4] 
= [x+4] *[x2 -9] 
so the zeros of this equation are -4 , 3, -3