What are the real zeros of x^3 + 4x^2 − 9x − 36

1 answer:

6 0

X3 + 4x2 -9x -36
[x3 + 4x2] -9 [ x+4]
take x2 common factor from first praket
x2[x+4] -9 [x+4]
= [x+4] *[x2 -9]
so the zeros of this equation are -4 , 3, -3

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